Question

Oh man stands on his balcony 120 feet above the ground he looks at the ground this site line forming a angle of 50° with the building and sees a bus stop the function D = 120 sec models the distance from the man to any object given his angle of sight 0. How far is the bus stop from the man.

Answer 1

Answer:

The bus stop is approximately 186.687 feet far from the man.

Step-by-step explanation:

Here, the given function that shows the distance from the man to any object in the ground,

$D=120 sec\theta$

Where, $\theta$ is the angle of his site line.

Given,

The site angle of man is 50° when he sees a bus stop,

That is, $\theta = 50^{\circ}$

Hence, the distance of bus stop from the man is,

$D = 120 sec 50^{\circ}$

$=120(1.55572382686)$

$=186.686859223\approx 186.687$

Hence, the bus stop is approximately 186.687 feet far from the man.

Answer 2

Answer:

Answer a 187 ft