"8 in., 15 in., 17 in." is a right triangle and "<span><span>4 in., 15 in., 17 in.</span>" is not a right triangle. Hope this helps!</span>
K=4
add seven on both sides
2x-4y=7
add 4y on both sides
2x=7+4y
divide 2 on both sides
x=7+4y/2
plug that into original equation
2(7+4y/2)-4y-7=0
7 and 4y cancel out
2(2)=0
4=0
???????? Left or right ???!!!
Answer:
Step-by-step explanation:
The given circle has equation

The equation of a circle with center (h,k) and radius r units is



<h2>❖ Tip❖ :- </h2>
This is the equation that has its center at the origin with radius 4 units.
When this circle is translated seven units to the right and five units up, then the center of the circle will now be at (7,5).