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Dimas [21]
4 years ago
13

Your job pays 6$ per hour write a variable expression for your pay in dollars for working h hours what is your Pay if you work 3

2 hours
Mathematics
1 answer:
kipiarov [429]4 years ago
4 0
6h

Fill in 32 for h

6x32

For 32 hours, you would earn $192
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= =
Leviafan [203]

Answer:

3x^{2}+14x+8

Step-by-step explanation:

(3x+2)(x+4)

(3x*x)+(3x*4)+(2*x)+(2*4)

3x^{2}+12x+2x+8

3x^{2}+14x+8

3 0
3 years ago
The perpendicular distance of the point from x axis is 2 units and the perpendicular distance from y axis is 3 units.Write the c
marysya [2.9K]

Answer:

Step-by-step explanation:

Given that :

the  perpendicular distance of the point from x axis = 2 units

the perpendicular distance from y axis is 3 units

The objective is to the write the coordinates of the points if it lies in

(i) | Quadrant  (ii) || Quadrant (iii) ||| Quadrant (iv) |v Quadrant

The position of a point in a plane is conveniently specified by the distances fro two perpendicular lines.The lines are called the x-axis and y-axis and their [point of intersection is called the origin.

The perpendicular distance from the y-axis is called the x- coordinate or abscissa and the perpendicular distance from x-axis is called the y-coordinate or ordinate,The  coordinate form an ordered pair with the abscissa written as first.

With that be said, So In the given question,

the  perpendicular distance of the point from x axis = 2 units

y coordinate = ±2

the perpendicular distance from y axis is 3 units

x coordinate = ±3

The ordered pair of the coordinates = ( ±3, ±2)

Therefore;

in | quadrant ; we have (3,2)   where  x and y are both on the positive axis

in || quadrant ; we have (-3,2)   x is on the negative axis and y is on the positive axis

In ||| quadrant ; we have (-3. -2) both x and y are on the negative axis

In |v quadrant ; we have ( 3, -2)  x is on the positive axis and y is on the negative axis.

5 0
4 years ago
Solve for x:<br> 27^(2x)=(1/9)^(x-3)
elena-14-01-66 [18.8K]
27^{2x}=\left(\dfrac{1}{9}\right)^{x-3}\\\\(3^3)^{2x}=\left(\dfrac{1}{3^2}\right)^{x-3}\\\\3^{3\cdot2x}=(3^{-2})^{x-3}\\\\3^{6x}=3^{-2(x-3)}\\\\3^{6x}=3^{-2x+6}\iff6x=-2x+6\ \ \ |add\ 2x\ to\ both\ sides\\\\8x=6\ \ \ |divide\ both\ sides\ by\ 8\\\\x=\dfrac{6}{8}\\\\\boxed{x=\frac{3}{4}}
3 0
3 years ago
Read 2 more answers
Please help me with the right answer kitties it’s pretty easy but I can’t do it because of my lazy butt
Yuri [45]

Answer:

It is D and if you don't the y-values increase by 9.

5 0
3 years ago
Pllsss help
torisob [31]

Answer:

[8.6,oo)

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
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