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kompoz [17]
3 years ago
6

What is the derivative of arcsin(6x)

Mathematics
1 answer:
schepotkina [342]3 years ago
8 0
\bf sin^{-1}(6x)\\\\
-----------------------------\\\\
\textit{using the chain-rule}\implies \cfrac{d}{dx}\left[ sin^{-1}(6x) \right]\implies \cfrac{1}{\sqrt{1-(6x)^2}}\cdot 6\\\\ \cfrac{6}{\sqrt{1-36x^2}}
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On a 8.5 x 11 inches (or larger) paper, create a carnival game (for example it could be: throwing a dart at a target, ball throu
Keith_Richards [23]

The probability of winning the game is 0.065

<h3>The description of the game</h3>

The game involves throwing two darts at two targets.

To win the game, the darts must hit anywhere in the following shapes

  • Rectangle: 5 by 4 inches
  • Circle: Radius, r = 3 inches

<h3>The probability of winning</h3>

The area of the paper is:

Area = 8.5 inches * 11 inches

Area = 93.5 square inches

The area of the rectangle on the paper is:

Area = 5 inches * 4 inches

Area = 20 square inches

The area of the circle on the paper is:

Area = π * (3 inches)²

Area = 28.3 square inches

The probability of landing on both shapes is

P(Both) = 20/93.5 * 28.3/93.5

Evaluate

P(Both) = 0.065

Hence, the probability of winning the game is 0.065

Read more about probability at:

brainly.com/question/24756209

#SPJ1

7 0
1 year ago
PLEASE HELP LIKE RN!!!!
olga55 [171]

Answer:

4 years

Step-by-step explanation:

Look for the year where the green bar is higher than the red bar.

8 0
3 years ago
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Matrix multiplication was used to encode a message using the given encoding matrix: [i 47 A=1 |-1 -3] The original message was c
nadya68 [22]

Answer:

A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] message SHOW_ME_THE_MONEY_  

Step-by-step explanation:

The matrix

A=\left[\begin{array}{cc}1&4\\-1&-3\end{array}\right]\rightarrow |A|=(1 \times -3)-(-1\times 4)=1\\\rightarrow A^{-1}=\left[\begin{array}{cc}-3&-4\\1&1\end{array}\right] \\

We can check that in fact A*A^⁻1=I_2 the identity matrix of size 2 x 2.

Now the message was divided in 1 x 2 matrices, then we have that the sequence given is the result of multiplying m by A, so to get m again we multiply now by A^⁻1. and we get the next table

Encoded message    Decoded message    message in letters by association

11 52        19 8    S H

-8 -9         15 23  O W

-13 -39        0 13   _ M

5 20         5 0   E _

12 56        20 8    T H

5 20         5 0    E _

-2 7           13 15  M O

9 41         14 5   N E

25 100       25 0    Y _

Then the message decoded is SHOW_ME_THE_MONEY_                                

3 0
2 years ago
Marco would like to hang a banner over his shoe store. He has two ladders and would like to know how high above the ground each
GuDViN [60]
13 divided by 11.3 is 1.150442477876106. So 15 by 1.150442477876106 and you get 13.03846162772485. Just round it to the nearest tenth and you get 13.0.
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2 years ago
What’s 437727x9018 ?
makvit [3.9K]
3947422086
is the answer hope it helps:)
7 0
3 years ago
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