Complete Question
A juggler tosses a bowling pin in the air with an initial velocity of 18 ft per second. It leaves his hand when it is five feet from the ground and he catches it when it is four feet from the ground,How long is the ball in the air?
Answer:

Step-by-step explanation:
From the question we are told that
Initial velocity 
Initial Height 
Final Height 
Generally the Newtons equation for motion is mathematically given by

Where

And

Therefore



Generally the equation for Time is mathematically Given as




Therefore the time spent on air by the ball is

Answer:
The height of the hill = h = 580.7 feet
Step-by-step explanation:
Let height of the hill = h
From the triangle A B D
Tan 22 = 
⇒ AB = h & B D = y + 700
⇒ Tan 22 =
------------(1)
From triangle ABC
Tan 38 = 
⇒ AB = h & BC = y
⇒ Tan 38 =
------------------(2)
⇒ h = y tan 38 -----------------(3)
Put the value of h from equation (3) into equation (1) we get
⇒ (tan 22) × (y + 700) = y × tan 38
⇒ 0.40 y + 282.82 = y × 0.78
⇒ y = 742.12 feet -----------------(4)
Put this value of y in equation 3 we get
⇒ h = 742.12 × tan 38
⇒ h = 580.7 feet
This is the height of the hill.
i think it’s 7, angle GHE