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3 years ago

Solve the linear system below using the substitution method. y = 5x – 22 3x +2y=34

Mathematics

2 answers:

valina [46]3 years ago

8 0

Answer:

x = 6 , y = 8 ( 6 , 8 )

Step-by-step explanation:

If we solve the linear system that you gave us,

y = 5x – 22

3x +2y=34

We get that x is 6 and y is 8.

In other words, since it's a point, it should be, ( 6 , 8 )

insens350 [35]3 years ago

6 0

Answer:

Use photo math, it will explain all the steps

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Can someone solve this for me please.

nika2105 [10]

Answer:

The value of PR is 21 ft.

Step-by-step explanation:

We know that:

3(PQ + QT + TP) = PR + RS + SP
PQ = 7 ft.
QT = 4 ft
RS = 12 ft.

Work:

3(PQ + QT + TP) = PR + RS + SP
=> 3(7 + 4 + TP) = PR + 12 + SP
=> 21 + 12 + 3TP = PR + 12 + SP
=> 21 + 3TP = PR + SP
=> 21 + SP = PR + SP [3TP = SP]
=> 21 = PR

Hence, the value of PR is 21 ft.

Hoped this helped.

$BrainiacUser1357$

6 0

2 years ago

What is 2 1/6 plus 3 and 1/4

Alex777 [14]

5 5/12

(2+3) 1/6 + 1/4=

5 5/12

5 0

3 years ago

natima [27]

Answer:

See explanation

Step-by-step explanation:

Let x be the number of spade shovels, y -the number of flat shovels and z - the number of square showels sold that day.

The store keeps an inventory of 80 shovels, then

x+y+z=80

The store always buy twice as many spade shovels as square, so

x=2z

The total cost of all shovels is

16x+9.60y+12.80z=1,072

a) The system of three equations is

$\left\{\begin{array}{l}x+y+z=80\\ \\x=2z\\ \\16x+9.60y+12.80z=1,072\end{array}\right.$

b) In matrix form this is

$\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}80\\0\\1,072\end{array}\right)$

c) The determinant is

$\left\|\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 16&9.60&12.80\end{array}\right\|=0-32+9.60-0+19.20-12.80=-16$

d) Find three determinants:

$\left\|\begin{array}{ccc}80&1&1\\ 0&0&-2\\ 1,072&9.60&12.80\end{array}\right\|=0-2,144+0-0+1,536-0=-608$

$\left\|\begin{array}{ccc}1&80&1\\ 1&0&-2\\ 16&1,072&12.80\end{array}\right\|=0-2,560+1,072-0+2,144-1,024=-368$

$\left\|\begin{array}{ccc}1&1&80\\ 1&0&0\\ 16&9.60&1,072\end{array}\right\|=0+0+768-0-0-1,072=-304$

So,

$x=\dfrac{-608}{-16}=38\\ \\y=\dfrac{-368}{-16}=23\\ \\z=\dfrac{-304}{-16}=19$

e) If the store doubled all prices and inventory, then the new matrix is

$\left(\begin{array}{ccc}1&1&1\\ 1&0&-2\\ 32&19.20&25.60\end{array}\right)\cdot \left(\begin{array}{c}x\\y\\z\end{array}\right)=\left(\begin{array}{c}160\\0\\2,144\end{array}\right)$