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vlabodo [156]
3 years ago
7

Which of these points lies on a circle centered at A(3, 3) and passing through B(6, 5)? A. C(1, 6) B. D(6, 0) C. E(0, 3) D. F(3,

-1) E. G(3, 6).
Mathematics
1 answer:
sleet_krkn [62]3 years ago
7 0
 we are given with a circle with the center at (3,3) and one that passes through (6,5). The equation of a circle is (x-h)^2 + (y-k)^2 = r^2. In this case h = 3 and k = 3. Substituting, h and k and x = 6 and y = 5, r^2 is obtained to be 13. Among these points, A. point (1,6) fits to the equation. 
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The length of a rectangle is
melomori [17]

Answer:

L= 11 m and W = 2 m

Step-by-step explanation:

Let's convert the sentences into mathematical expressions, for which we need to assign letters to the unknowns: length and width of a rectangle.

Let's identify the rectangle's length with the letter "L', and its width with the letter "W".

Then we can write:

"The length of a rectangle is  3  meters more than  4  times the width."

as: L = 4 * W + 3

The second sentence says:

"The area (of the rectangle) is 22 square meters", so to write this in mathematical terms we need to recall the formula for the area of a rectangle:

Area = Length * Width   (the product of the rectangle's length times its width)

Therefore the second sentence can be converted into the following equation:

Area = L * W = 22

Now we can use the first mathematical expression we constructed in the second formula so we can reduce the number of unknowns  from two (L and W) to only one (W) and solve for it in the equation.

We replace "L" with 4 * W + 3 (from our first expression) in the area formula:

L * W = (4 * W + 3) * W = 22

4W^2 + 3W = 22\\4W^2+3W-22=0

Which is a quadratic equation in W, and which has solutions given by the quadratic formula:

ax^2+bx+c=0\\

x=\frac{-b+/- \sqrt{b^2-4ac} }{2a}

For our unknown W (instead of "x") and our parameters:

a=4, b=3, c=-22

the quadratic formula would be:

W=\frac{-3+/- \sqrt{3^2-4(4)(-22)} }{2(4)}=\frac{-3+/- \sqrt{9+352} }{8}= \frac{-3+/- \sqrt{361} }{8}=\frac{-3+/-19 }{8}This gives as two possible solutions (one using the plus and the other using the minus):

W=\frac{-3-19}{8} =\frac{-22}{8}=-\frac{11}{4} \\W=\frac{-3+19}{8} =\frac{16}{8}=2 \\

the negative answer has no physical meaning in our case because we are dealing with positive dimensions for a rectangle. Therefore the only logical solution for W is: 2 meters

Now we use the first expression we found for "L" to find its value:

L = 4 (2) +3 = 8 + 3 = 11 meters

7 0
4 years ago
Can some one give me the answers to this
patriot [66]
6. (2,1)  7. substitution  9. x=0 10. y=25

I hope this helps please give me a crown and a like if you think I deserve it and if you have any more questions just friend me and ask away.

8 0
3 years ago
Read 2 more answers
Dy/dx = (cos x) e^(y+sinx) and y = 0 when x = 0. find the original equation
Korvikt [17]
Find the general solution by separating the variables then integrating: 
dy / dx = cosx℮^(y + sinx) 
dy / dx = cosx℮ʸ℮^(sinx) 
℮^(-y) dy = cosx℮^(sinx) dx 
∫ ℮^(-y) dy = ∫ cosx℮^(sinx) dx 
-℮^(-y) = ℮^(sinx) + C 
℮^(-y) = C - ℮^(sinx) 
-y = ln[C - ℮^(sinx)] 
y = -ln[C - ℮^(sinx)] 

Find the particular solution by solving for the constant: 
When x = 0, y = 0 
-ln(C - 1) = 0 
ln(C - 1) = 0 
C - 1 = 1 
C = 2 
<span>y = -ln[2 - ℮^(sinx)]


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!</span>
3 0
3 years ago
11.)-If PQRS is a parallelogram, find the values of x and y.
defon

Step-by-step explanation:

For no. 11

13x + 15 = 19x - 9 ( being opposite sides of parallelogram)

19x - 13x = 15 + 9

6x = 24

x = 4

Also,

4y + 7 ° + 10y - 37° = 180° { being co-interior angles }

14y - 30° = 180°

14y = 210°

y = 210° / 14

y = 15°

For no. 12

5x + 38° = 8x - 19° { being opposite angles of parallelogram }

8x - 5x = 38° + 19°

3x = 57°

x = 19°

Hope it will help :)

4 0
3 years ago
T is a monomial that is equal to (-5x3y2)(3x y).<br> What is the degree of T?
dimulka [17.4K]
If t is a monomial then the degree of t would be one(1)
3 0
4 years ago
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