(a+2)(a-1) - (a+1)(a-2), if a = 2
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To solve for the area of a triangle, we multiply the length and height, then divide that by two. L = 10. H = 7.
To solve for the perimeter, or edges, of the triangle, we need to use the Pythagorean Theorem: a² + b² = c² to solve for the third side. We already know two measures: 10 and 7. Now we need to square them, add them together to get c², then take the root of that number.
We cannot simplify √149, so we either leave it, or round it.
This is rounded to the nearest 10,000.
Now that we have the measure of the longest side, we can add all three sides together to get the perimeter of the triangle.
The first thing we must do is find the amount of land that will be used for the 120 lots.
We must remember that 10% of the land will not be used for the lots.
We have then:
Then, we must consider the following conversion of units:
Applying the conversion we have:
Then, the amount of square feet for each lot is given by:
Answer:
There will be 32670 square feet in each lot.
We must remember that 10% of the land will not be used for the lots.
We have then:
Then, we must consider the following conversion of units:
Applying the conversion we have:
Then, the amount of square feet for each lot is given by:
Answer:
There will be 32670 square feet in each lot.
Given: NQ = NT , QS Bisect NT(∴ NS=ST ) , TV Bisects QN (∴ NV=VQ )
To Prove: QS=TV
Proof: In ΔNQT
NQ=NT
∴ VQ=ST
In a isosceles triangle, If two sides are equal then their opposites angles are equal.
∴ ∠NQT=∠NTQ ( ∵ NQ=NT)
In ΔQST and TVQ
ST=VQ (sides of isosceles triangle)
∠NQT=∠NTQ (Prove above)
QT=TQ (Common)
So, ΔQST ≅ TVQ by SAS congruence property
∴ QS=TV (CPCT)
CPCT: Congruent part of congruence triangles.
Hence Proved