A trig identity is <span>asinucosu=<span>a/2</span>sin(2u)</span>So you can write your equation as<span>y=sin(x)cos(x)=<span>1/2</span>sin(2x)</span>Use the crain rule here<span><span>y′</span>=<span>d/<span>dx</span></span><span>1/2</span>sin(2x)=<span>1/2</span>cos(2x)<span>d/<span>dx</span></span>2x=cos(2x)</span>The curve will have horizontal tangents when y' = 0.<span><span>y′</span>=0=cos(2x)</span>On the interval [-pi, pi], solution to that is<span><span>x=±<span>π4</span>,±<span><span>3π</span>4</span></span></span>
Answer:
B
Step-by-step explanation:
The equation of a circle is
(x-h)^2 + (y-k)^2 = r^2
h= 9, k = -7
r = 2, so r^2 = 4.
We now know that the equation must equal 4, so we can rule out answers A and C.
Plug in the values for h and k to get
(x-9)^2 + (y+7)^2 = 4
Choice B is correct!
Answer:
(y - -2) (6 - 3) - (2 - -2) (x - 3) = 0
6y + 2 - 3y - 6 -2x +6 +2x +6 = 0
3y +8 =0
3y = -8
y = -8/3
Step-by-step explanation:
