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3 years ago

PLEASE! 50 Points!!!!!!

Mathematics

2 answers:

natta225 [31]3 years ago

8 0

(4,1) (0,2) (8,3).

done the topic

lianna [129]3 years ago

4 0

We are given a triangle on the graph.

The vertices of the given triangle are (1,3), (-3,4) and (5,5).

The shown triangle is being transformed by the following rule

(x, y)→(x+3, y−2).

Let us apply same rule in each of the above coordinate

(1,3) →(1+3, 3 -2) → ( 4,1)

(-3,4) →(-3+3, 4 -2) → ( 0, 2)

(5,5) →(5+3, 5 -2) → ( 8, 3).

<h3>Therefore, coordinates of the transformed triangle are (4,1), (0,2) and (8,3).</h3>

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Factorise fully 6x + 9x cubed

o-na [289]

Answer:

$3375x^3$

Step-by-step explanation:

→ $\left(6x\:+\:9x\right)^3$

→ $\left(15x\right)^3$ [ add the x inside the bracket ]

→ $15^3x^3$ [ remove the bracket ]

→ $3375x^3$ [ final answer ]

6 0

2 years ago

Read 2 more answers

The age of the children in kindergarten on the first day of school is uniformly distributed between 4.8 and 5.8 years old. A fir

Kazeer [188]

Answer:

(1) (c) 5.30 years.

(2) (b) 0.289.

(3) (b) 0.80.

(4) (d) 0.50.

(5) (a) 5.25 years.

Step-by-step explanation:

Let X = age of the children in kindergarten on the first day of school.

The random variable X follows a continuous Uniform distribution with parameters a = 4.8 years and b = 5.8 years.

The probability density function function of X is:

$f_{X}(x)=\left \{ {{\frac{1}{b-a}} ;\ a$

(1)

The expected value of a Uniform random variable is:

$E(X)=\frac{1}{2}(a+b)$

Compute the mean of X as follows:

$E(X)=\frac{1}{2}(a+b)=\frac{1}{2}\times (4.8+5.8)=5.3$

Thus, the mean of the distribution is (c) 5.30 years.

(2)

The standard deviation of a Uniform random variable is:

$SD(X)=\sqrt{\frac{1}{12}(b-a)^{2}}$

Compute the standard deviation of X as follows:

$SD(X)=\sqrt{\frac{1}{12}(b-a)^{2}}=\sqrt{\frac{1}{12}\times (5.8-4.8)^{2}}=0.289$

Thus, the standard deviation of the distribution is (b) 0.289.

(3)

Compute the probability that a randomly selected child is older than 5 years old as follows:

$P(X>5)=\int\limits^{5.8}_{5} {\frac{1}{5.8-4.8}}\, dx\\$

$=\int\limits^{5.8}_{5} {1}\, dx\\=[x]^{5.8}_{5}\\=(5.8-5)\\=0.8$

Thus, the probability that a randomly selected child is older than 5 years old is (b) 0.80.

(4)

Compute the probability that a randomly selected child is between 5.2 years and 5.7 years old as follows:

$P(5.2$

$=\int\limits^{5.7}_{5.2} {1}\, dx\\=[x]^{5.7}_{5.2}\\=(5.7-5.2)\\=0.5$

Thus, the probability that a randomly selected child is between 5.2 years and 5.7 years old is (d) 0.50.

(5)

It is provided that a randomly selected child is at the 45th percentile.

This implies that:

P (X < x) = 0.45

Compute the value of x as follows:

$P (X < x) = 0.45$

$\int\limits^{x}_{4.8} {\frac{1}{5.8-4.8}}\, dx=0.45$

$\int\limits^{x}_{4.8} {1}\, dx=0.45$

$[x]^{x}_{4.8}=0.45$

$x-4.8=0.45\\$

$x=0.45+4.8\\x=5.25$

Thus, the age of the child at the 45th percentile is (a) 5.25 years.

6 0

3 years ago

Choose the expression equivalent to 2^ -2 x 2^5.

Katarina [22]

Answer:

2³

Step-by-step explanation:

Using the rule of exponents

$a^{m}$ × $a^{n}$ = $a^{(m+n)}$ , thus

$2^{-2}$ × $2^{5}$ = $2^{(-2+5)}$ = 2³ [ = 8 ]

8 0

3 years ago

Aryon has $15. He buys 2 Cokes that each cost $1.00. He also buys a

fenix001 [56]

15.00-5.00-2.00-2.00= $6.00

7 0

3 years ago

Please help for best I need good grade

Roman55 [17]

Answer:

i think its #2 or #4

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers