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melomori [17]
3 years ago
6

casey has a small business making dessert baskets. she estimates that her fixed weekly costs for rent, electricity, and salaries

are $200. the ingredients for one dessert basket cost $2.50. casey’s total costs for last week were $500. how many dessert baskets did she make?
Mathematics
1 answer:
m_a_m_a [10]3 years ago
3 0
500 = 200 + 2.50x
x = amount of dessert baskets

500 - 200 = 300.
300 = 2.50x
300 ÷ 2.50 = 120.
Casey made 120 dessert baskets.
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BabaBlast [244]

Answer:

The minimum number of words left to write is 215

Step-by-step explanation:

Let

w -----> the number of words left to write

we know that

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w+285\geq 500

Solve for w

Subtract 285 both sides

w\geq 500-285\\w\geq 215

The minimum number of words left to write is 215

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3 years ago
A new gas- and electric-powered hybrid car has recently hit the market. The distance traveled on 1 gallon of fuel is normally di
Doss [256]

Answer:

a) P [ Z > 70 ]  = 0.1075  or 10.75 %

b)  P [ Z < 60 ] = 0.1038   or  10.38 %

c)  P [ 55 ≤ Z ≤ 70 ] =  0.8882   or 88.82 %

Step-by-step explanation:

Normal Distribution  μ = 65    and σ = 4

a) The probability of the car travels more than 70 miles per gallon is:

P [ Z > 70 ]  =  (Z-μ) ÷ σ  ⇒   P [ Z > 70 ] = (70-65) ÷4     P [ Z > 70 ] = 1.25

the point 1.25 corresponds at values, from left tail up to 70 so we must go and look for the area for the point 1.24 which is 0.8925. Then we have the area or probability of all cars traveling up  to 70 miles therefore  we have to subtract 1 -0,8925

P [ Z > 70 ]  = 0.1075  or 10.75 %

b)The probability of the car travels less than 60 miles per gallon is:

P [ Z < 60 ]  = ( 60 - μ ) ÷  σ ⇒  P [ Z < 60 ] = (60-65)÷ 4    P [ Z < 60 ] = -1.25

Again -1.25 corresponds to 60 miles per gallon threfore we move to the left and find for point -1.26  which area is 0.1038 so

P [ Z < 60 ] = 0.1038     10.38 %

c) P [ 55 ≤ Z ≤ 70]

For  point  Z = 70 or 1.25 (case a above)  P [ Z ≤ 70] = (70-65)÷4  

P [ Z ≤ 70] = 1.25

In this case we got the whole area from the left tail up to 1.25

P [ Z ≤ 70]  = 0.8944 (includes the area of the point from the left tail up to the point assocciated to 55 miles and for that reason we have to subtract that area)

P [ Z ≥ 55 ]  = (55-65) ÷ 4     P [ Z ≥ 55 ] = -2.5  and the area is 0.0062

So P [ 55 ≤ Z ≤ 70 ] =  0.8944 - 0.0062  = 0.8882

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Round the answer to the nearest
kykrilka [37]

By knowing the <em>blood</em> pressure and applying the <em>quadratic</em> formula, the age of a man whose normal <em>blood</em> pressure is 129 mm Hg is 40 years old.

<h3>How to use quadratic equations to determine the age of a man in terms of blood pressure</h3>

In this problem we have a <em>quadratic</em> function that models the <em>blood</em> pressure as a function of age. As the latter is known, we must use the quadratic formula to determine the former:

129 = 0.006 · A² - 0.02 ·A + 120

0.006 · A² - 0.02 · A - 9 = 0

A = \frac{0.02 \pm \sqrt{0.006^{2}-4\cdot (0.006)\cdot (- 9)}}{2\cdot (0.006)}

A = 1.667 + 38.733

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By knowing the <em>blood</em> pressure and applying the <em>quadratic</em> formula, the age of a man whose normal <em>blood</em> pressure is 129 mm Hg is 40 years old.

To learn more on quadratic equations: brainly.com/question/1863222

#SPJ1

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