Answer:
F (pp) = 0.04
F (Pp) = 0.32
F (PP) = 0.64
Explanation:
Studying population genetics, we used the Hardy-Weinberg equilibrium model. In the case of snails, the H-W principle predicts that the total number of cases in the population should follow the following equation: PP + 2.Pp + pp = 200.
If a population has 200 snails and 8 are affected by a recessive condition, we have 4% affected, or 0.04.
This means that 0.04 corresponds to p², and p corresponds to 0.2.
Therefore, P is equal to 0.8 because p + P = 1.
Knowing the allele frequencies, we go to the frequency of the genotypes.
F (pp) = p² = 0.04 = 8 snails
F (Pp) = 2.Pp = 0.32 = 64 snails
F (PP) = P² = 0.64 = 128 snails
Answer:
The likelihood of having blue offspring equals 3/16 (1/16 AAbb + 2/16 Aabb)
Explanation:
Due to technical problems, you will find the complete explanation in the attached files
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