Answer:
3 seconds
Step-by-step explanation:
You want to set h(t)=3, then take the root such that t≠0. You would have:
3=3+48t−16t^2
Let's solve your equation step-by-step.
3=3+48t−16t2
Step 1: Simplify both sides of the equation.
3=−16t2+48t+3
Step 2: Subtract -16t^2+48t+3 from both sides.
3−(−16t2+48t+3)=−16t2+48t+3−(−16t2+48t+3)
16t2−48t=0
Step 3: Factor left side of equation.
16t(t−3)=0
Step 4: Set factors equal to 0.
16t=0 or t−3=0
t=0 or t=3
3 makes more sense than 0 because the ball can't have been in the air for 0 seconds.
So the ball was in the air for 3 seconds.
219,544.50 is the correct answer because add it up
10
20
30 there u go
that the rounding
Answer:
The total number of boxes of canned food brought in by the three grades is 17.63 boxes
Step-by-step explanation:
To find the total number of canned foods brought in by the three grades, we will have to add the number of canned foods brought by each of the grades to each other. Careful attention has to be paid to the decimal points.
Canned foods brought by 6th graders: 5.75 boxes
Canned foods brought by 7th graders: 6.5 boxes
Canned foods brought by 6th graders: 7/1.3 boxes
We may have a slight challenge adding in 7/1.3 boxes to the other figures. What we can do now is to evaluate it to a decimal value by dividing it up.
7/ 1.3 will be the same thing as 7 divided by 1.3 = 5.38 boxes.
hence, we have 5.75 +6.5+ 5.38= 17.63 boxes
The total number of boxes of canned food brought in by the three grades is 17.63 boxes
It is equal. because if the numbers are the same size and the denominator are the same it is equal
