Julie has the three segments shown in the graph. Can she make a triangle with these segments.

Mathematics

2 answers:

FinnZ [79.3K]4 years ago

7 0

Answer:

ppl the answers A

Step-by-step explanation:

According to the triangle inequality if a, b, and c are lengths of the legs of a triangle then a + b > c. If you measure the segments, their measurements are 5, 5, and

and 5 + 5 >

. Therefore, Yes, the segments do meet the triangle inequality.

bagirrra123 [75]4 years ago

5 0

Answer:

Step-by-step explanation:

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2(a³+b²+11)+1(3+a³+b+11)

Ann [662]

Answer:

$2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36$

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

$2(a^3+b^2+11)+1(3+a^3+b+11)$

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

$2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14$