The chances that NEITHER of these two selected people were born after the year 2000 is 0.36
<h3>How to determine the probability?</h3>
The given parameters are:
Year = 2000
Proportion of people born after 2000, p = 40%
Sample size = 2
The chances that NEITHER of these two selected people were born after the year 2000 is calculated as:
P = (1- p)^2
Substitute the known values in the above equation
P = (1 - 40%)^2
Evaluate the exponent
P = 0.36
Hence, the chances that NEITHER of these two selected people were born after the year 2000 is 0.36
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oh no noooooooooooooooooooooooooooooooooooooooooooo
Answer:
A
Step-by-step explanation:
Since the triangle is right use Pythagoras' identity to find EF
The square on the hypotenuse is equal to the sum of the squares on the other two sides, that is
EF² + DF² = DE² ← substitute values
EF² + 12² = 18², that is
EF² + 144 = 324 ( subtract 144 from both sides )
EF² = 180 ( take the square root of both sides )
EF = 
→ A
Answer:
The answer to your question is below
Step-by-step explanation:
pH definition
pH = - log [H⁺]
a) For pH = 2.4, solution A
2.4 = -log[H⁺]
[H⁺] = antilog⁻².⁴
[H⁺] = 0.00398
For pH = 9.4, solution B
[H⁺] = antilog⁻⁹.⁴
[H⁺] = 3.98 x 10⁻¹⁰
b) Divide hydrogen-ion concentration of solution A by hydrogen-ion concentration of solution B.
0.00398 / 3.98 x 10⁻¹⁰
10000000 times
c) By 7, because 7 is the number of zeros
Answer:
Probability of the day to be a snow day is 0.34
Step-by-step explanation:
We have the data,
Out of 21 which had less than 3 inches of snow, 5 were snow days.
Out of 8 days which had more than 3 inches of snow, 6 were snow days.
So, we get,
Total number of days = 21 + 8 = 29
Total number of snow days = 5 + 6 = 11
Thus, the probability that the day will be a snow day is 
i.e. 0.34
Hence, the probability of the day to be a snow day is 0.34.
