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yawa3891 [41]
3 years ago
14

A flock of geese is flying north for the summer while a bird watcher is observing. He notices that they are flying in the shape

of an absolute value graph. The lead goose is 5 miles east and 3 miles north of the bird watcher. A second goose is flying 1 mile east and 2 miles north of the bird watcher. If the bird watcher is standing at the origin write an equation for the flight of the geese in the form of y=a|(x-h)|+k
Mathematics
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

y = -¼│x − 5│+ 3

Step-by-step explanation:

y = a│x − h│+ k

(h, k) is the vertex of the absolute value graph.  In this case, it's (5, 3).

y = a│x − 5│+ 3

One point on the graph is (1, 2).  Plug in to find the value of a.

2 = a│1 − 5│+ 3

2 = 4a + 3

a = -¼

Therefore, the graph is:

y = -¼│x − 5│+ 3

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Answer:

y(x)=sin(2x)+2cos(2x)

Step-by-step explanation:

y''+4y=0

This is a homogeneous linear equation. So, assume a solution will be proportional to:

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Now, substitute y(x)=e^{\lambda x} into the differential equation:

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Using the characteristic equation:

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Where:

e^{\lambda x} \neq 0\\\\for\hspace{3}any\hspace{3}\lambda

Therefore the zeros must come from the polynomial:

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These roots give the next solutions:

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Where c_1 and c_2 are arbitrary constants. Now, the general solution is the sum of the previous solutions:

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Using Euler's identity:

e^{\alpha +i\beta} =e^{\alpha} cos(\beta)+ie^{\alpha} sin(\beta)

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y(x)=c_1sin(2x)+c_2cos(2x)

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Finally, the solution is given by:

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Answer:

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Step-by-step explanation:

i honestly dont know if this answer is right but i am currently takeing classes in math about Geometry. We was learning about Word problems, that had to do with volume, Area, and perimeter, and learned what radius is, etc..

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Answer:

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No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.

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No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.

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