Question

two square regions have an area of 125 and 5 how many yards of fencing is needed to enclose? ( assume regions fenced separately)

Answer 1

Answer:

$24\sqrt{5}\ yards$

Step-by-step explanation:

Let A1 be the area of one square and A2 be the area of second square

So,

A1 = s^2

where s is side of square

$s^2=125\\\sqrt{s^2}=\sqrt{125}\\s=\sqrt{25*5}\\ s= \sqrt{5^2 * 5}\\ s= 5\sqrt{5}$

So side of one square is $5\sqrt{5}$

To calculate the length of fence we need to find the perimeter of the square

So,

P1 = 4 * s

$=4*5\sqrt{5} \\=20\sqrt{5}$

For second square:

$A_2=s^2\\5=s^2\\\sqrt{s^2}=5\\{s}=\sqrt{5}$

The perimeter will be:

$P_2 = 4*s\\=4 * \sqrt{5} \\=4\sqrt{5}$

So the total fence will be: P1+P2

$= 20\sqrt{5}+4\sqrt{5} \\= 24\sqrt{5}\ yards$