Answer:
Answer B ![(-\infty,1)U(1,2]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C1%29U%281%2C2%5D)
Step-by-step explanation:
Notice that the quotient of f(x)/g(x) is:

therefore, this new function imposes conditions due to the fact that it has a square root in the numerator and a binomial in the denominator both with the variable x. Then, in order for the root in the numerator to be defined, the argument inside the root must be larger than or equal to zero. That is:

So, this condition must be satisfied by the x-values of the domain.
Then we have the binomial in the denominator, which in order to be defined needs to be different from zero. Notice that the only x-value that could cause problems (render zero) is:

Then, 
So we have to eliminate the number 1 from the previous subset that required x smaller than or equal to 2.
The way to represent this Domain is then: ![(-\infty,1)U(1,2]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C1%29U%281%2C2%5D)
Answer:
A pythagorean identity means that for any angle
,
.
This also means
The symbol, theta (
) represents one of the acute angles in the right triangle. The hypotenuse (familiarly c in the regular pythagorean theorem) is 1. The triangle base is
, and the height (side perpendicular to the base, making a right angle) is
. The angle theta is opposite the
side.
Step-by-step explanation:
The pythagorean theorem applies to right triangles, which always have a 90 degree angle. Pythagorean identities are used to simplify trigonometric expressions/evaluate trig functions and to find the trig ratios in a right triangle.
Answer:
1. false
2. false
3. false
4. true
Step-by-step explanation:
a quadritilateral always has 4 sides, but it dpesnt HAVE to be a square
a parrellelogram can be any shap as long as its parrelel
a rhombus is always a square, becuase if you turn it around... VIOLA! you get a square.
Answer:
<h2>A) 32</h2>
Step-by-step explanation:
From 1 to 10 we have 4 numbers which are {2,4,6,8}
From 10 to 20 we have 4 numbers which are {12,14,16,18}
.
.
.
From 70 to 78 we have 4 numbers which are {72,747,6,78}
<em><u>conclusion:</u></em> we 4×8 number = 32