Find the coordinates of the midpoint of line HX.. . H(0,0), X(8,4)

1 answer:

3 0

X = (0 + 8)/2 = 4
<span>y = (0 + 4)/2 = 2 </span>
<span>so midpoint is (4, 2) </span>

we solved it by using mid point formulae

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3 years ago

What is the value of x in the equation<br> 4z +16<br> 12<br> = х - 4?

Serhud [2]

<h3>Solution:</h3>

$\frac{4x + 16}{12} = x - 4 \\ = > 4x + 16 = 12(x - 4) \\ = > 4x + 16 = 12x - 48 \\ = > 16 + 48 = 12x - 4x \\ = > 64 = 8x \\ = > x = \frac{64}{8} \\ = > x = 8$

<h3>Answer:</h3>

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2 years ago

Which is the interval notation represent the domain?

Kazeer [188]

Answer:

The first choice, $(-\infty, 7) \cup (7, \infty)$ .

Step-by-step explanation:

The dashed vertical line is a vertical asymptote. The x-coordinate of all points on this vertical asymptote are equal to 7. In other words, when the x-value of a point on the graph approaches $7$ , its y-value approaches infinity (or negative infinity.)

Either way, the graph is not defined for $x = 7$ . The point $7$ should thus be excluded from the domain of the graph.

The graph is apparently defined for all other x-values. The domain of the function should thus be all real numbers with the exception of $x = 7$ . Here's how to write that in interval notation:

The set of all real numbers can be expressed as the interval $(-\infty, \infty)$ . Note that infinity $\infty$ (or $(- \infty)$ itself isn't a real number. The round brackets indicate that both endpoints are excluded from the from the interval.
The set of all real numbers less than (not equal to) $7$ is $(-\infty,7 )$ (both ends are excluded.) The set of all real numbers greater than (not equal to) $7$ is $(7, \infty)$ .
The set of all real numbers that is not equal to $7$ is the union of all real numbers less than $7$ and all real numbers greater than $7$ . The union operator $\cup$ connects two intervals.