Answer:
(2,7) is not a solution to the given system of equations.
Step-by-step explanation:
Given system of equation is:
2x + 3 = y
2x + y = 15
To check whether (2,7) is solution to this system or not, we will put x=2 and y=7 in both equations.
Putting x=2 and y=7 in Eqn 1
2(2) + 3 = 7
4 + 3 = 7
7 = 7
Thus the ordered pair satisfies the equation
Putting x=2 and y=7 in Eqn 2
2(2) + 7 = 15
4 + 7 = 15
11 ≠ 15
The ordered pair do not satisfy the second equation.
Hence,
(2,7) is not a solution to the given system of equations.
<h3>
Answer: 3/5</h3>
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Explanation:
The set {1, 2}U{2, 6, 7, 9}U{5, 6, 7} simplifies to {1,2,5,6,7,9} after we combine everything and sort the values. We toss any duplicates.
Let B = {1,2,5,6,7,9}
There are 6 items in set B out of 10 items in set A.
The probability of landing in set B, if you pick something randomly from A, is 6/10 = 3/5
The equation for the quadratic variation is:
y = kx^2
Plug in x and y values to solve for 'k'
32 = k(2^2)
32 = 4k
k = 32/4 = 8
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She brought 48 pieces. The equation is x/12=4
