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3 years ago

Plz answer the question in the ss

Mathematics

1 answer:

Volgvan3 years ago

4 0

Answer:

$33+11\sqrt{3}$ .

Step-by-step explanation:

sin(30º) = 0,5

$\frac{1}{2} = \frac{b}{c} \\ b = \frac{c}{2} \\ b = 11.$

$c^2=a^2+b^2 \\ a^2 = c^2-b^2\\ a^2=22^2-11^2 \\ a^2 = 484 - 121 = 363 \\ a = \sqrt{363} \\ \sqrt{363} = \sqrt{3*121} = 11\sqrt{3}.$

$P = a+b+c \\ P = 11+22+11\sqrt{3} \\ P = 33+ 11\sqrt{3}.$

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3 years ago

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$f(x-3)=x^2-4x+5\\\\f((x-3)+3)\to\text{put x + 3 to the equation of the function:}\\\\f(x-3+3)=(x+3)^2-4(x+3)+5\\\text{use the distributive property and}\ (a+b)^2=a^2+2ab+b^2\\f(x)=x^2+2(x)(3)+3^2+(-4)(x)+(-4)(3)+5\\f(x)=x^2+6x+9-4x-12+5\qquad\text{combine like terms}\\f(x)=x^2+(6x-4x)+(9-12+5)\\f(x)=x^2+2x+2\\\\f(1-x)\to\text{put 1 - x to the equation of the funtion f(x):}\\\\f(1-x)=(1-x)^2+2(1-x)+2\\\text{use the distributive property and}\ (a-b)^2=a^2-2ab+b^2$

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