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andreev551 [17]
2 years ago
7

(1 point) Let y=ex/5. Find the differential dy when x=2 and dx=0.2 Find the differential dy when x=2 and dx=0.01

Mathematics
1 answer:
Deffense [45]2 years ago
7 0

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Differential Calculus.

Since, we know this is a definite calculus,

thus we get here as, by using the Chain Rule.

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emmasim [6.3K]
Surface are of a rectangular prism = 2(l x w + l x h + w x h) = 2(10 x 3 + 10x + 3x) = 2(30 + 13x) = 60 + 26x

Volume of a rectangular prism = l x w x h = 10 * 3 * x = 30x

Since surface area = volume
60 + 26x = 30x
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7 0
3 years ago
What is the unit rate in miles per hour if Kelly walks 6 miles in 1.5 hours?
sammy [17]

Answer:

4 miles per hour.

Step-by-step explanation:

6/1.5 = 4

6 0
3 years ago
I need help with problem 27,28,29
Rom4ik [11]
27 has to be C
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5 0
3 years ago
Read 2 more answers
If A = (4,-5) and B = (7.-9), what is the length of AB?​
Nookie1986 [14]

Answer:

5

Step-by-step explanation:

We can figure out the length of AB by using the distance formula.

D = \sqrt{(7-4)^{2} + (-9-(-5))^{2} }\\ D = \sqrt{(3)^{2} + (-4)^{2} }\\D = \sqrt{9 + 16}\\D = \sqrt{25}\\D=5

So the distance is 5

5 0
3 years ago
Ok need help this is the question :Use the Pythagorean theorem to write an equation for the distance Jane's trainer bikes.
IRINA_888 [86]

Answer:

<em>Jane traveled 8 miles farther then her trainer</em>

Step-by-step explanation:

<u>The Pythagora's Theorem</u>

In any right triangle, the square of the measure of the hypotenuse is the sum of the squares of the legs. This can be expressed with the formula:

c^2=a^2+b^2

Where

c = Hypotenuse or largest side

a,b = Legs or shorter sides

Jane's path from the Health Club to the end of her route describes two sides of a right triangle of lengths a=16 miles and b=12 miles.

Her total distance traveled is 16 + 12 = 28 miles

Her trainer goes directly from the Health Club to meet her through the hypotenuse of the triangle formed in the path.

We can calculate the length of his route as:

c=\sqrt{16^2+12^2}

c=\sqrt{256+144}=\sqrt{400}=20

c = 20 miles

The difference between their traveled lengths is 28 - 20 = 8 miles

Jane traveled 8 miles farther then her trainer

8 0
3 years ago
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