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Sophie [7]
3 years ago
15

Which figure is shown? prism pyramid cylinder cone

Mathematics
1 answer:
hoa [83]3 years ago
5 0
Hi, do you have to picture?
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What means the same as 65?
Alina [70]

Answer:6 × 5 and 5 + 5 + 5 + 5 + 5 6 + 6 + 6 + 6 + 6

Step-by-step explanation:

3 0
3 years ago
In the diagram, FG=34, GH=288, and HJ=256. Is GH tangent to circle F?
Anastaziya [24]

Answer:

No

Step-by-step explanation:

If GH is tangent to circle F, then it forms a right angle with FG.  Therefore, triangle FGH would be a right triangle and would satisfy Pythagorean theorem.

34² + 256² = 288²

66692 = 82944

The sides are not a Pythagorean triple, so GH is not tangent to the circle.

6 0
3 years ago
Solve the equation: k^2+5k+13=0
mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}  \\

From the question

a = 1 , b = 5 , c = 13

So we have

k =  \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)}  \\  =  \frac{ - 5 \pm \sqrt{25 - 52} }{2}  \\  =  \frac{ - 5 \pm \sqrt{ - 27} }{2}  \:  \:  \:  \:  \:  \:  \\  =  \frac{ - 5  \pm3 \sqrt{3}  \: i}{2}  \:  \:  \:  \:  \:  \:

<u>Separate the solutions</u>

k_1 =  \frac{ - 5 + 3 \sqrt{3} \: i }{2}  \:  \:  \:  \: or \\ k_2 =  \frac{ - 5 - 3 \sqrt{3}  \: i}{2}

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

k_1 =  -  \frac{5}{2}  +  \frac{3 \sqrt{3} }{2}  \: i \:  \:  \:  \: or \\ k_2 =  -  \frac{5}{2}  -  \frac{3 \sqrt{3} }{2}  \: i

Hope this helps you

8 0
3 years ago
There are 40 girls and 60 boys in the math club the coach wants to divide the entire club into teams where each team has the sam
lapo4ka [179]
40 and 60
40 = 20 x 2
60 = 20 x 3

GCF = 20

<span>the greatest number of teams coach can make is 20
each team can have 2 girls and 3 boys</span>
6 0
3 years ago
What is the relationship between the two ratios?
antoniya [11.8K]
10/14 = 5/7
30/36 = 5/6

answer
not proportional
4 0
3 years ago
Read 2 more answers
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