A. Which reduction should she use so the picture fills as much of the frame as possible, without being too large?
Find the scale factor to get rom 7 1/3 inches to 5 1/3 inches:
5 1/3 / 7 1/3 = 0.7272
Now rewrite the fraction as decimals:
2/3 = 0.667
¾ = 0.75
5/9 = 0.555
The closest scale that would still fit the frame would be 2/3 because it is under 0.727.
B. How much extra space is there in the frame when she uses the reduction from Part A?
Multiply the original size by the scale factor to use:
7 1/3 x 2/3 = 4 8/9
Now subtract the scaled size from the original size:
7 1/3 – 4 8/9 = 2 4/9 inches extra
C. If she had a machine that could reduce by any amount, so that she could make the reduced picture fit in the frame exactly, what fraction would the reduction be?
Convert the scale from part A to a fraction:
0.72 = 72/99 which reduces to 8/11
Answer:
Option B. $0.70
Step-by-step explanation:
First day fine = $0.10
Second day fine (doubled or $0.30 which is lesser)
= $0.10 + $0.10 [$0.10 is lesser than $0.30]
= $0.20
Third day fine = $0.20 + $0.20 [ $0.20 is lesser than $0.30]
= $0.40
Fourth day fine = $0.40 + $0.30 = $0.70
[$0.30 is cheaper than doubling the amount $0.40 + $0.40]
Therefore, the total fine for a book on the fourth day is $0.70
Answer:
The answer is x=57
Step-by-step explanation:
First, we would set the number to x.
Then, we turn the words into an equation.
x+75 = 3x-39
Isolate the x.
-2x = -114
So...
x = 57
3c-d
3c-(-c+7)
3c+c-7
4c-7
Final answer: 4c-7
