Answer:
a) = 8 in
b) When the length of AC = in. and BC = in. = 10 in
c) When the length of AB = 10.2 in. and BC = 3.7 in. = 6.5 in
d) When the length of AB = in. and BC = in. in. = in
Step-by-step explanation:
a) When the length of AC = 5 in. and CB = 3 in. we have;
The length of = AC + CB (segment addition postulate)
Therefore;
= 5 in. + 3 in. = 8 in.
b) When the length of AC = in. and BC = in. we have;
The length of = AC + CB (segment addition postulate)
Therefore;
= in.+ in. = 10 in.
c) When the length of AB = 10.2 in. and BC = 3.7 in. we have;
The length of = AB - BC (converse of the segment addition postulate)
Therefore;
= 10.2 in.+ 3.7 in. = 6.5 in.
d) When the length of AB = in. and BC = in. in. we have;
The length of = AB - AC (converse of the segment addition postulate)
Therefore;
= in. - in.= in.
Answer:
see explanation
Step-by-step explanation:
A difference of 2 squares factors in general as
a² - b² = (a - b)(a + b)
(x - 1)² - 25 ← is a difference of squares
with a = x - 1 and b = 5, thus
(x - 1)² - 25
=(x - 1 - 5)(x - 1 + 5) = (x - 6)(x + 4), then
(x - 6)(x + 4) = 0
Equate each factor to zero and solve for x
x - 6 = 0 ⇒ x = 6
x + 4 = 0 ⇒ x = - 4
Solutions are x = - 4, x = 6
D) Picking up 12 kids for a party and then dropping 12 kids off at the pool
Answer:
-2
Step-by-step explanation:
if showing in graph would be minus 2