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Kruka [31]
3 years ago
13

I'm confused can u help​

Mathematics
1 answer:
Xelga [282]3 years ago
5 0
Nope no no no no ko no no no no
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The limit of sqrt(9x^4 + 1)/(x^2 - 3x + 5) as x approaches infinity is
Lerok [7]

Answer:

B. 3.

Step-by-step explanation:

At the limit we can take the numerator  to be √(9x^4) = 3x^2

The function is of the form ∞/ ∞ as x approaches ∞ so we can apply l'hopitals rule:

Differentiating top and bottom we have   6x / 2x - 3. Differentiating again we get 6 / 2 = 3.

Our limit as x  approaches infinity  is 3.

6 0
3 years ago
If f(x)= x2 + 1 and g(x) = 3x + 1, find 2f(1) + 3g(4)<br><br> •45<br> •43<br> •42
Alex73 [517]

Answer:

the answer is 43.

Step-by-step explanation:

We have functions

f(x) = x^2+1

g(x)=3x+1,

and we want to evaluate

2f(1) + 3g(4)

For this we first evaluate f(1) and g(4) separately:

f(1)=(1)^2+1=2

g(4)=3(4)+1=13

Therefore

2f(1) + 3g(4)= 2(2)+3(13)=43

So we have

\boxed{2f(1) + 3g(4)=43}

3 0
4 years ago
Create a polynomial that has 10 roots.
Colt1911 [192]

Answer:

(x – 3)(x + 5)(x + ½) = (x2 + 2x – 15)(x + ½) = x3 + 2.5x2 – 14x – 7.5

7 0
3 years ago
10.
SpyIntel [72]

Answer:

44

Step-by-step explanation:

is times 5.5

6 0
3 years ago
Please help me out!!
dybincka [34]

Answer:

I can't really help u with this because I already struggle enough with this kind of math that I don't even learn it any more.

Step-by-step explanation:

But I hope the other person answers the problem for u and know how to do this one.

8 0
3 years ago
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