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omeli [17]
3 years ago
12

Solve the quadratic equation 4x2 – 2x = 9 using the quadratic formula

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
7 0

Here you go.

I really hope I helped. Good luck.

koban [17]3 years ago
3 0

Answer:

x= 1 + or - sr37/4 got it from a sitr

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Work out the balance for £240 invested for 20 years at 7% per annum
Luda [366]

Step-by-step explanation:

It depends in the type on interest

Simple Interest

PxRxT

£240 x 0.07x 3 = £50.4

£240 + £50.4 = £290.4

Compound Interest

Px(1+R)^T

£290.4 x (1 + 0.07)³ = £355.7524872= €355.76

5 0
3 years ago
Help me please I am begging y’all
cupoosta [38]
2 is the answer i think
7 0
3 years ago
Find the volume of the given prism round to nearest tenth
allochka39001 [22]

Answer:

308.2

Step-by-step explanation:

A=2(wl+hl+hw)=2*(3.9*13.2+6*13.2+6*3.9)≈308.16cm^2

≈ is approximately

3 0
3 years ago
Read 2 more answers
Solve the following system of equations using the substitution method.
BartSMP [9]

Answer:

B

Step-by-step explanation:

First label the equations.

6x +3y= 18 -----(1)

y= -2x +5 -----(2)

subst. (2) into (1):

6x +3(-2x +5)= 18

6x +3(-2x) +3(5)= 18 (expand)

6x -6x +15= 18

15= 18 (simplify)

(reject)

There is no solution.

<u>Further explanation</u><u>:</u>

If I rewrite the first equation into the form of y=mx+c, I would get

6x +3y=18

3y= 18 -6x (bring y term to one side)

y= 6- 2x (÷3 throughout)

y= -2x +6

Notice that the gradients of both lines are equal ( -2). This implies that they are parallel to each other and will never meet. Hence there are no solutions.

3 0
3 years ago
In a certain sequence, each term, starting with the 3rd term, is found by multiplying the previous two terms. what is the differ
mina [271]
From F.S 1, consider this series : 8, 1, 8, 8, 64, 64*8. 

Again, consider the series 2, 1/4, 1/2, 1/8, 1/16, 1/(8*16). Clearly, the difference of the 6th and the 3rd term is different for them. Insufficient.

<span>From F.S 2, let the series be </span><span><span>a,b,ab,a<span>b2</span>,<span>a2</span><span>b3</span>,<span>a3</span><span>b5</span></span><span>a,b,ab,a<span>b2</span>,<span>a2</span><span>b3</span>,<span>a3</span><span>b5</span></span></span><span>. Now we know that </span><span><span>a<span>b2</span>=1</span><span>a<span>b2</span>=1</span></span>. The required difference =<span><span><span>a3</span><span>b5</span>−ab=ab(<span>a2</span><span>b4</span>−1)=ab[(a<span>b2</span><span>)2</span>−1]</span><span><span>a3</span><span>b5</span>−ab=ab(<span>a2</span><span>b4</span>−1)=ab[(a<span>b2</span><span>)2</span>−1]</span></span><span>= 0.Sufficient.</span>
5 0
3 years ago
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