Answer:
1520.53
Step-by-step explanation:
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Answers:
When we evaluate a logarithm, we are finding the exponent, or <u> power </u> x, that the <u> base </u> b, needs to be raised so that it equals the <u> argument </u> m. The power is also known as the exponent.
![5^2 = 25 \to \log_5(25) = 2](https://tex.z-dn.net/?f=5%5E2%20%3D%2025%20%5Cto%20%5Clog_5%2825%29%20%3D%202)
The value of b must be <u> positive </u> and not equal to <u> 1 </u>
The value of m must be <u> positive </u>
If 0 < m < 1, then x < 0
A <u> logarithmic </u> <u> equation </u> is an equation with a variable that includes one or more logarithms.
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Explanation:
Logarithms, or log for short, basically undo what exponents do.
When going from
to
, we have isolated the exponent.
More generally, we have
turn into ![\log_b(m) = x](https://tex.z-dn.net/?f=%5Clog_b%28m%29%20%3D%20x)
When using the change of base formula, notice how
![\log_b(m) = \frac{\log(m)}{\log(b)}](https://tex.z-dn.net/?f=%5Clog_b%28m%29%20%3D%20%5Cfrac%7B%5Clog%28m%29%7D%7B%5Clog%28b%29%7D)
If b = 1, then log(b) = log(1) = 0, meaning we have a division by zero error. So this is why ![b \ne 1](https://tex.z-dn.net/?f=b%20%5Cne%201)
We need b > 0 as well because the domain of y = log(x) is the set of positive real numbers. So this is why m > 0 also.
-4g is what I got if ur evaluating
If it’s something about slope I got -4
No, it is not. This is because "%" refers to "percent" which means per hundred or over one hundred. Therefore, 0.6% = 0.6*0.01 = 0.006$.
Well what are the numbers they give you