Question

Given: Isosceles trapezoid EFGH

Answer 1

Given: An Isosceles trapezoid EFGH in which EF =GH

To prove: ΔFHE ≅ ΔGEH

Proof: In Isosceles trapezoid EFGH, Considering two triangles ΔFHE and ΔGEH

  1. FE ≅ G H   → [ Given]

  2. ∠H = ∠E

→ Draw GM⊥HE and FN ⊥EH, and In Δ GMH and ΔFNE,

                          GH=FE [Given]

          ∠M+∠N=180° so GM║FN and GF║EH, So GFMN is a rectangle.]

∴ GM =FN [opposite sides of rectangle]

∠GMH = ∠FNE [ Each being 90°]

Δ GMH ≅ ΔFNE  [ Right hand side congruency]

→∠H =∠E [CPCT]

→ Side EH is common i.e  EH ≅ EH .

→ΔFHE ≅ ΔGEH. [SAS]

Answer 2

1. isosceles trapezoid
2. FEH
3. GHE
4. reflexive
5.SAS
These answers are correct on edge