Answer:
20
Step-by-step explanation:
Givens
Let child one = x
Let child two = y
Let child three = z
Equations
x^2 + y^2 + z^2 = 100
xy + xz + yz = 150
Solution
There's a trick here. The square of their weights added together is equal (with some modification) to the given conditions. Start by squaring (x+y+z).
(x + y + z)^2 = x^2 + y^2 + z^2 + 2xy + 2xz + 2yz
Take out 2 as a common factor from the last three terms.
(x + y + z)^2 = (x^2 + y^2 + z^2+ 2(xy + xz + yz) )
Substitute the given conditions into the equation. (x^2 + y^2 + z^2) = 100 and 2*(xy + xz + yz) = 2 * 150
(x + y + z)^2 = 100 + 2*150
(x + y + z)^2 = 100 + 300
(x + y + z)^2 = 400
Take the square root of both sides.
sqrt(x+y+z)^2 = sqrt(400)
x + y + z = 20
Note
This answer tells you nothing about the values of x y and z. On the other hand it does not ask for the values of x y and z.
If n is rational, it means that
Therefore when we do n² we can write it as
Remember that the product of two integer numbers is also an integer, therefore we can guarantee that
Then we can confirm that n² is the quotient of two integers and the denominator is not zero, therefore, n² is always rational, it cannot be an irrational number
Answer:
Incomplete problem - reword
Step-by-step explanation:
Answer:
if ∠Q=∠R
draw an angular bisector from P to QR in which it intersect wit Qr at point S
now we have two triangle : QPS and RSP
in which angle : QPS=RPS ( PS is angular bisector)
and we have angle Q and angle R are equal
and PS is common side
this makes triangle QPS and RSP are congruent by AAS(angle angle side)
which also means that pQ=PR ( proved)
1. We need to get rid of all the denominator in this equation.
- This can be done by multiplying left and right sides by the LCD.
- In the problem: 12/x = 8, the LCD is X.
12/x = 8 is now 12 = x * 8
1a. 8 * x = 8x
Now, your answer is 3/2, but It's improper. Let's convert it into a mixed number.
Subtract 3 by 2.
3 - 2 = 1
3/2 = 1 1/2
Therefore, your answer is 1 1/2. Also, the answer is 1.5.
