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Luden [163]
3 years ago
15

Find the nonpermissible replacement for N in the following expression : -8/5n

Mathematics
2 answers:
Allisa [31]3 years ago
7 0

The correct answer is

n=0


EXPLANATION



This is testing your knowledge on domain of rational functions.


To avoid division by zero, the denominator of the rational function


\frac{-8}{5n}


should not be equal to zero.



Therefore the non permissible number can be found by equating the whole denominator to zero. That is,



5n=0



We can now solve for n, to obtain,




n=\frac{0}{5}=0



Hence that number is


n=0




NeTakaya3 years ago
6 0

We are given expression

\frac{-8}{5n}

we know that

this is rational expression

And any rational expression is undefined when it's denominator =0

so, for finding non-permissible values of n , we set denominator =0

and then we can solve for n

denominator is 5n

5n=0

Divide both sides by 5

\frac{5n}{5} =\frac{0}{5}

so, we get

n=0

So, the non-permissible replacement for n in this expression is 0.........Answer

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Answer:

E\ n\ F = \{1, 5, 6,7\}

F\ n\ G =\{9\}

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Step-by-step explanation:

Given

S = \{1,2,3,4, 5,6,7,8, 9, 10, 11, 12\}

E = \{1,2, 3, 4, 5, 6,7\}

F =\{1,5,6, 7, 8,9\}

G = \{9,10, 11, 12\}

H = \{2, 3, 4\}

Solving (5): E and F

Sets of E and F = E n F

E\ n\ F = \{1,2, 3, 4, 5, 6,7\}\ n\ \{1,5,6, 7, 8,9\}

List out common elements

E\ n\ F = \{1, 5, 6,7\}

<em>They are not mutually exclusive because </em>n(E\ n\ F) \neq 0<em />

Solving (6): F and G

Sets of F and G = F n G

F\ n\ G =\{1,5,6, 7, 8,9\}\ n\ \{9,10, 11, 12\}

List out common elements

F\ n\ G =\{9\}

<em>They are not mutually exclusive because </em>n(F\ n\ G) \neq 0<em />

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Sets of F or G = F U G

F\ U\ G =\{1,5,6, 7, 8,9\}\ U\ \{9,10, 11, 12\}

List all elements without repetition

F\ U\ G =\{1,5,6, 7, 8,9,10, 11, 12\}

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P(F\ U\ G) = \frac{n(F\ U\ G)}{n(S)}

n(F\ U\ G) = 9

n(S) = 12

Hence;

P(F\ U\ G) = \frac{9}{12}

Divide by 3

P(F\ U\ G) = \frac{3}{4}

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