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musickatia [10]
4 years ago
10

Can some one help me with this?:

Mathematics
1 answer:
Studentka2010 [4]4 years ago
7 0
2.6pi is the circumference 
circumference is 2pi*r
so 2.6pi=2pi*r
2.6=2r
r=1.3
The radius should be 1.3 meters
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Let f(x) = (x − 3)−2. find all values of c in (1, 4) such that f(4) − f(1) = f '(c)(4 − 1). (enter your answers as a comma-separ
Verizon [17]

If the function is (x-3)^{-2} and  f(4) − f(1) = f '(c)(4 − 1) then there is not any answer.

Given function is (x-3)^{-2} and  f(4) − f(1) = f '(c)(4 − 1).

In this question we have to apply the mean value theorem, which says that given a secant line between points A and B, there is at least a point C that belongs to the curve and the derivative of that curve exists.

We begin by calculating f(2) and f(5):

f(2)=(2-3)^{-2}

f(2)=1

f(5)=(5-3)^{-2}

f(5)=1

And the slope of the function:

f^{1}(x)=f(5)-f(2)/(5-2)

f^{1}(c)=0

Now,

f^{1} (x)=-2*(x-3)^{-3}

=-2(x-3)^{-3}

=0

-2 is not equal to 0. So there is not any answer.

Hence if the function is (x-3)^{-2} and  f(4) − f(1) = f '(c)(4 − 1) then there is not any answer.

Learn more about derivatives at brainly.com/question/23819325

#SPJ4

7 0
2 years ago
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