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2 years ago

Could someone please help me find the domain and range of the equation?...and B-64 a. Please??

Mathematics

1 answer:

alexandr1967 [171]2 years ago

6 0

<h3>B-61. C=</h3><h3><u>Domain:</u></h3>

0 < x < ∞

x > 0

<h3><u>Range:</u></h3>

y ≥ 500

9 − 3 = 4 − 3

5 − 3 = −3

5 = 0

= 0

Hope this helps you ! :)

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Simplify the expression<br><br>cot^2x - cot^2x cos^2x

andrew-mc [135]

Cot^2x - cot^2x cos^2x
= cot^2x - {(cot^2x)(cos^2x)}
= cot^2x { 1 - cos^2x }
= cot^2x { sin^2x }
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= cos^2x

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3 years ago

5 less than a number y is under 20.

klio [65]

Answer:

y - 5 < 20

y < 25

Step-by-step explanation:

y - 5 < 20

y < 25

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3 years ago

What is the slope-intercept equation for the line below?

Kryger [21]

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3 years ago

-45 / -5 = <br> plz can you help me

garri49 [273]

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3 years ago

Read 2 more answers

J. Reexamine the sequence 20, 14, 8, 2, ... from the problem

DENIUS [597]

Answer:

The n th of the given sequence is $t_{n} = 26-6 n$

Step-by-step explanation:

<u>Step 1</u> :-

Given sequence is 20,14,8,2,.......this sequence in arithmetic progression but this sequence is decreasing sequence.

given first term is 20 and difference is $d = second term- first term = 14-20=-6$

now the nth term of given sequence is

by using formula $t_{n}=a+(n-1)d$

$t_{n}= 20+(n-1)(-6)$

$t_{n}= 20-6 n+6$

final answer:-

$t_{n} = 26-6 n$

<u>verification</u>:-

$t_{n} = 26-6 n$

put n=1 we get first term is 20

put n=2 we get second term is 14

put n=3 we get third term is 8

put n=4 we get fourth term is 2

so the n th term of sequence is

$t_{n} = 26-6 n$

3 0

3 years ago