I can't get what do you need, but I guess it's a part of java code. I can explain what it means. It's used to unite two rising sorted arrays which are list1 and list2. The result is stored in result array. I suggest you to clearly explain your task as it's difficult to give you correct answer.
Specification of database requirements falls under which category of database administration?
b. development
Answer:
the answer is D.All of the above
Answer:
The answer is : When there is a need to copy a formula and have the references update based on the new location
Explanation:
<em>I often use this function in any spreadsheet document. Imagine, you have thousands of data in a single sheet. And you inserted one row or column. Normally, you have to update EACH CELL's formula. Imagine the work load and the effort you need to exert. But when the single cell updates all the cell's reference, formula will be affected and you don't need to re update all the cells. It saves you time and effort and worries.</em>
Answer:
#include <iostream>
#include <string>
#include <stack>
#include <math.h>
using namespace std;
int main() {
string s;
double n=0;
int position=0;
stack<int> wholeNumbers;
cout<<"Enter a decimal number:";
cin>>s;
string::iterator counter = s.begin();
while(*counter!='.' && counter!=s.end()){
wholeNumbers.push(*counter-48);
counter++;
position=position+1;
}
for(int i=0;i<position;i++){
n=n+(wholeNumbers.top()*pow(10,i));
wholeNumbers.pop();
}
position=-1;
if(counter!=s.end()){
counter++;
}
while(counter!=s.end()){
n=n+((*counter-48)*pow(10,position));
position=position-1;
counter++;
}
cout<<n;
}
Explanation:
- Inside the while loop, push the push a number to the wholeNumbers stack by subtracting it with 48.
- Increment the counter and position variable by 1 inside the while loop.
- Count the number of digit, push each digit to top of stack and find the end of the number,
- Run a for loop up to the value of position variable and pop a value from the wholeNumbers stack.
