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neonofarm [45]
3 years ago
8

One of your start-ups uses error-correcting codes, which can recover the original message as long as at least 1000 packets are r

eceived (not erased). Each packet gets erased independently with probability 0.8. How many packets should you send such that you can recover the message with probability at least 99%
Computers and Technology
1 answer:
Marina CMI [18]3 years ago
5 0

Answer:

Number of packets ≈ 5339

Explanation:

let

X = no of packets that is not erased.

P ( each packet getting erased ) = 0.8

P ( each packet not getting erased ) = 0.2

P ( X ≥ 1000 ) = 0.99

E(x) = n * 0.2

var ( x ) = n * 0.2 * 0.8

∴ Z = X - ( n * 0.2 ) / \sqrt{n*0.2*0.8}   ~ N ( 0.1 )

attached below is the remaining part of the solution

note : For the value of <em>n</em> take the positive number

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