Question

One of your start-ups uses error-correcting codes, which can recover the original message as long as at least 1000 packets are received (not erased). Each packet gets erased independently with probability 0.8. How many packets should you send such that you can recover the message with probability at least 99%

Answer 1

Answer:

Number of packets ≈ 5339

Explanation:

let

X = no of packets that is not erased.

P ( each packet getting erased ) = 0.8

P ( each packet not getting erased ) = 0.2

P ( X ≥ 1000 ) = 0.99

E(x) = n * 0.2

var ( x ) = n * 0.2 * 0.8

∴ Z = X - ( n * 0.2 ) / $\sqrt{n*0.2*0.8}$   ~ N ( 0.1 )

attached below is the remaining part of the solution

note : For the value of n take the positive number