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UNO [17]
3 years ago
7

Which of the six trigonometric functions do not depend on the value of r?

Mathematics
1 answer:
trasher [3.6K]3 years ago
3 0
If we construct a triangle in a circle of radius r, the radius of the circle will be the hypotenuse of our triangle, and the legs will be x and y as you can see in the picture. 
Now we can construct our trigonometric ratios for our triangle as usual:
sin \alpha = \frac{y}{r}
cos \beta = \frac{x}{r}
tan \beta = \frac{y}{x}
csc \beta = \frac{r}{y}
sec \beta = \frac{r}{x}
cot \beta = \frac{x}{y}

As you can see the only two trigonometric functions that don't depend on the value of r are tangent and cotangent.

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Step-by-step explanation:

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What integer is the opposite of –7? A. 7 B. - 1/7 C. 1/7 D. -7
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7 0
3 years ago
Using Euclid's algorithm, find the HCF of 1651 and 2032. Express
Lelechka [254]

Answer:

Since 2032 gt 1651, we divide 2032 by 1651 to get 1 as quotient and 381 as remainder. step 2. Since the remainder 381≠0 , we divide 1651 by 381 to get 4 as quotient and 127 as remainder.

Step-by-step explanation:

Euclid algorithm lemma, a = bq + r where 0 ≤ r < b

From Euclid algorithm lemma, 2032 = 1651 × 1 + 381

Using lemma for 1651 and 381, e.g., 1651 = 381 × 4 + 127

Similarly, use lemma for 381 and 127, e.g., 381 = 127 × 3 + 0

Hence, HCF = 127

Now, 127 = 1651M + 2032 N

⇒127 = (127 × 13)M + (127 × 16)M

⇒1 = 13M + 16 N

Here many solutions possible because we have one equation contains two variable.

Assume M = 5 and N = -4

Then, 13 × 5 + 16 × -4 = 65 – 64 = 1

So, HCF of 1651 and 2032 in the form of 1651M + 2032 N is [1651(5) + 2032(-4)]

8 0
3 years ago
The length of a photograph is 3 cm less than twice the width. The area is 54 cm^2. Find the dimensions of the photograph?
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4 0
4 years ago
Algebra 1 please help​
Nina [5.8K]

Answer:

that seems hard

Step-by-step explanation:

i cant see the pic tho

6 0
3 years ago
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