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2 years ago

Please help me! ——————————

Mathematics

1 answer:

Lelechka [254]2 years ago

7 0

Answer:

msksk1928728(192773)22881288296;+512166:+

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If √3 = 1.73 to 2 dp, find the value of 4/√3 to 2 dp

Mashutka [201]

Answer:2.31

Step-by-step explanation: considering that the root of 3 has already been given. Will just divide 4 by the root of 3 which is 1.73. and the answer it gives is 2.31

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3 years ago

Monica’s retirement party cost two dollars, plus an additional three dollars for every guess she invites. If there are 16 guests

lesya692 [45]

Answer:

TWO BUCKS?? ballin on a budget

anyways, if there are 16 guests, the party would cost $50. sounds a lot more correct lol

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2 years ago

How do u graph slope

Makovka662 [10]

You graph slope by going up and over based on what number you have as the slope. The starting point is the y intercept

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3 years ago

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

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2 years ago

Write each fraction in simplest form

mihalych1998 [28]

Answer:

1. 10 in / 3 ft

2. 5 min / 1 h

3. 1 kg / 250 g

Step-by-step explanation:

4 0

2 years ago