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attashe74 [19]
3 years ago
7

(4x3 – 2x2 + 3x – 1) + (5r2 - x - 5). What is the sum ?

Mathematics
1 answer:
Lunna [17]3 years ago
3 0

The sum is 4x³ + 3x² + 2x – 6.

Solution:

The correct question is given below.

(4x³ – 2x² + 3x – 1) + (5x² – x – 5). What is the sum?

<u>To find the sum of the polynomial:</u>

Sum of (4x³ – 2x² + 3x – 1) and (5x² – x – 5)

           = (4x³ – 2x² + 3x – 1) + (5x² – x – 5)

Remove the parentheses.

           = 4x³ – 2x² + 3x – 1 + 5x² – x – 5

Group like terms together.

           = 4x³ – 2x² + 5x² + 3x – x – 1 – 5

Add the similar elements. i.e the element with same power.

           = 4x³ + 3x² + 2x – 1 – 5

Subtract the constant terms.

           = 4x³ + 3x² + 2x – 6

The sum is 4x³ + 3x² + 2x – 6.

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Seats at a local entertainment venue sell for $5 each in the lower level and $4 each in the upper level. If all the seats
7nadin3 [17]

Step-by-step explanation:

wapsi ki Vidya kya hai Hindi mein

5 0
3 years ago
Q1: Identify the graph of the equation and write an equation of the translated or rotated graph in general form.
marin [14]

Answer:

C. hyperbola; 9x^2-25y^2-250y-850=0

Step-by-step explanation:

The given conic has equation:

9x^2-25y^2=225

Divide through by 225.

\frac{9x^2}{225}-\frac{25y^2}{225}=\frac{225}{225}

\frac{x^2}{25}-\frac{y^2}{9}=1

This is a hyperbola centered at the origin.

The hyperbola has been translated from the origin to (0,5).

The translated hyperbola will have equation;

\frac{(x-0)^2}{25}-\frac{(y-5)^2}{9}=1

Multiply through by 225.

9(x-0)^2-25(y-5)^2=225

Expand

9x^2-25(y^2-10y+25)=225

9x^2-25y^2+250y-625=225

Rewrite in general form;

9x^2-25y^2+250y-625-225=0

9x^2-25y^2+250y-850=0

3 0
3 years ago
Steps to solve: 28x - 12 + 2x - 4 - x
Musya8 [376]

Let's simplify by step

28x-12+2x-4-x

28x+-12+2x+-4+-x

Combine like terms

28x+-12+2x+-4+-x

(28x+2x+-x)+(-12+-4)

29x+-16

= 29x-16


I hope that's help !

8 0
3 years ago
What additional information could be used to prove ABC MQR using SAS?
Igoryamba

Answer:

To prove that ΔABC ≅ ΔMQR using SAS, we show that two sides with the intersection angle are congruent.

From the diagram, it is shown that CA is congruent to RM.

From the first option, given that m∠A = 64° and AB = MQ = 31 cm, then we have CA = RM, AB = MQ, and CAB = RMQ (i.e. m∠A = m∠M = 64°).

This shows that the first option is correct.

From the second option, given that CB = MQ = 29 cm, then we have CA = RM, CB = MQ, but ACB is not congruent to RMQ.

Thus the second option in not correct.

From the third option, m∠Q = 56° and CB ≅ RQ, then we have CA = RM, CB = RQ, ACB = 60°, but we do not know the value of MRQ.

Thus the third option is not correct.

From the fourth option, m∠R = 60° and AB ≅ MQ, then we have CA = RM, AB = MQ, RMQ = 64°, but we do not know the value of CAB.

Thus the fourth option is not correct.

From the fifth option, AB = QR = 31 cm, then we have CA = RM, AB = QR, but we do not know the value of CAB or MRQ.

Thus, the fifth option is not correct.

Therefore, the additional information that could be used to prove ΔABC ≅ ΔMQR using SAS is m∠A = 64° and AB = MQ = 31 cm

6 0
3 years ago
A 20.0 kg sled is being pulled across a horizontal surface at constant velocity. The pulling force has a magnitude of 80.0N and
SSSSS [86.1K]
U = F/R = 80/200cos30
u = 80/100√3
u= 0.46
7 0
4 years ago
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