The standard form of a parabole is: (y-k) = a(x-h)², Where (h , k) are the coordinates of the vertex
In the example Vertex (3,1) ,
so (y-1) = a(x-3)². (a)
Now let's calculate a. The y-intercept coordinates(0 , 10), Replace in (a) x by 0 & y by 10:
(10-1) = a(0 - 3)²
9 = 9a and a=1
<u />The equation becomes : y-1 = (x-3)², Expand (y-1) = x²-6x+9
<u />and finally y = x² - 6x +10 (ANSWER C)
Answer:
A) L = W + 6
B) L * W = 167 OR L = 167 / W
Substituting B) into A)
167 / W = W + 6
Multiplying both sides by "W" we get
167 = W^2 + 6W
W^2 + 6W -167
Solving by the quadratic formula
Width = 10.266
Length = 16.266
Step-by-step explanation:
Answer:
After adding 8 you get 14 = x/4.
Step-by-step explanation:
6=x/4-8 Add 8 to both sides:
6 + 8 = x/4 - 8 + 8
14 = x/4
x = 4*14
x = 56.
The numbers that would be smaller would be the two with the difference of 26.
27-1=26 where as, if you were to use a 1 in each, 99+1= 100. Therefore 27 and 1 (28) is less than 99 and 1 (100).
Answer:
the area is six units squared