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polet [3.4K]
3 years ago
11

I bought 5 burgers and 2 fries for 17.65 went back bought 2 burgers and 3 fries and paid 10.25. how much does one burger cost an

d how much does one fry cost​

Mathematics
1 answer:
Lana71 [14]3 years ago
4 0

Answer:

The cost of one burger is $2.95

The cost of one fry is $1.45

Step-by-step explanation:

Let

x----> the cost of one burger

y---> the cost of one fry

we know that

5x+2y=17.65 ----> equation A

2x+3y=10.25 ----> equation B

Using a graphing tool

Remember that the solution of the system of equations is the intersection point both graphs

The intersection point is (2.95,1.45)

see the attached figure

therefore

The cost of one burger is $2.95

The cost of one fry is $1.45

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attashe74 [19]

Answer:

45

Step-by-step explanation:

We are assuming that the pole's shadow and buildings shadow are proportional so our ratio is

x/36=1.9/1.52

cross multiply

1.52x=68.4

simplify

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6 0
3 years ago
How many positive integers between 1000 and 9999 inclusive
bekas [8.4K]

Answer:

Step-by-step explanation:

a.

first number is  1000-1+9=1008

9)1000(1

    9

-------

     10

       9

    -----

       10

         9

       ----

         1

       ----

last number is 9999

9| 9999

  ---------

    1111 |0

    --------

9999=1008+(n-1)9

9999-1008=(n-1)9

n-1=8991/9=999

n=999+1=1000

b.

first digit=1000

last digit=9999-1=9998

2 |9999

  ---------

  |4999|1

9998=1000+(n-1)2

(n-1)2=9998-1000=8998

n-1=4499

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c.not sure

d.

total  numbers=9000

9999=1000+(n-1)1

9999-1000=n-1

n=8999+1=9000

numbers divisible by 3=3000

first number=1002

last number=9999

9999=1002+(n-1)3

(n-1)3=9999-1002=8997

n-1=2999

n=2999+1=3000

numbers not divisible by 3=9000-3000=6000

e.

numbers divisible by 5=1800

first number=1000

last number=9995

9995=1000+(n-1)5

(n-1)5=9995-1000=8995

n-1=1799

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numbers divisible by 7=1286

7 | 1000

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  |  142-6

1000-6+7=1001

7 | 9999

  |---------

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first digit=1001

last digit=9996

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(n-1)7=9996-1001=8995

n-1=1285

n=1285+1=1286

numbers divisible by 35=257

first digit=1015

35 ) 1000 ( 28

        70

       ----

        300

        280

        ------

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1000-20+35=1015

35)9999(285

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last digit=9999-24=9975

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n-1=8960/35=256

n=257

reqd. numbers=1800+1286-257=3019

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Step-by-step explanation:

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