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polet [3.4K]
3 years ago
11

I bought 5 burgers and 2 fries for 17.65 went back bought 2 burgers and 3 fries and paid 10.25. how much does one burger cost an

d how much does one fry cost​

Mathematics
1 answer:
Lana71 [14]3 years ago
4 0

Answer:

The cost of one burger is $2.95

The cost of one fry is $1.45

Step-by-step explanation:

Let

x----> the cost of one burger

y---> the cost of one fry

we know that

5x+2y=17.65 ----> equation A

2x+3y=10.25 ----> equation B

Using a graphing tool

Remember that the solution of the system of equations is the intersection point both graphs

The intersection point is (2.95,1.45)

see the attached figure

therefore

The cost of one burger is $2.95

The cost of one fry is $1.45

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A rectangle has a length of 3.6 in, and a perimeter of 16.8 in.
zhannawk [14.2K]

Answer:

Width = 4.8 inches

Step-by-step explanation:

The perimeter of a rectangle is given by the formula:

P=2l+2w

Where

P is perimeter

l is length

w is width

Given length = 3.6 and perimeter = 16.8, we plug them in into the formula and figure out the width, w. Process shown below:

P=2l+2w\\16.8=2(3.6)+2w\\16.8=7.2+2w\\16.8-7.2=2w\\9.6=2w\\w=\frac{9.6}{2}\\w=4.8

Hence, the width is 4.8 inches

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3 years ago
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kherson [118]

Answer:

The answer is

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Step-by-step explanation:

Remember that Taylor says that

f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }

For this case

f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18

f(x) = {\displaystyle  8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }

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Rachael scored 12 points
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Answer:

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The volume of a cube is V^3

Therefore the volume can be calculated as follows

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