A = 5 + t
t + 3 = 2/3a
t + 3 = 2/3(5 + t)
t + 3 = 10 + 2t / 3
3t + 9 = 10 + 2t
t = 1
a = 5 + 1
a = 6
Let m and n be any integers so that 2m and 2k are two even numbers.
The product is 2m(2k) = 2(2mk), which is even.
Answer:
a=1, b=-2,c=-1
Step-by-step explanation:
1*(x)+(-2)*y+(-1)*1. a=1, b=-2,c=-1
Let's input the x value (5) and see if the output is correct (-1).
y = 2(5) - 11
y = 10 - 11
y = -1
(5, -1) is a solution to y = 2x - 11.
The only ordered pairs that are a solution to y = 8x are (2, 16), (1, 8), and (-3, -24).
y = 8(2)
y = 16
y = 8(1)
y = 8
y = 8(-3)
y = -24
