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3 years ago

Adjacent angles are congruent true or false

Mathematics

2 answers:

Leno4ka [110]3 years ago

5 0

The correct answer is false hope this helps

allsm [11]3 years ago

3 0

False.
Adjacent angles are simply next to each other connected. This does not mean that they have the same measure. Therefore they are NOT congruent.

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Which relation represents a function

BARSIC [14]

Answer:

A relation is a function if each element of the domain is paired with exactly one element of the range. If given a graph, this means that it must pass the vertical line test.

Step-by-step explanation:

3 0

3 years ago

Which ordered pairs are solutions to the inequality y−2x≤−3?

My name is Ann [436]

we will proceed to resolve each case to determine the solution

we have

$y-2x \leq -3$

$y\leq2x-3$

we know that

If an ordered pair is the solution of the inequality, then it must satisfy the inequality.

case a) $(5,-3)$

Substitute the value of x and y in the inequality

$-3\leq2*5-3$

$-3\leq7$ -------> is true

The ordered pair $(5,-3)$ is a solution

case b) $(0,-2)$

Substitute the value of x and y in the inequality

$-2\leq2*0-3$

$-2\leq-3$ -------> is False

The ordered pair $(0,-2)$ is not a solution

case c) $(-6,-3)$

Substitute the value of x and y in the inequality

$-3\leq2*-6-3$

$-3\leq-15$ -------> is False

The ordered pair $(-6,-3)$ is not a solution

case d) $(1,-1)$

Substitute the value of x and y in the inequality

$-1\leq2*1-3$

$-1\leq-1$ -------> is True

The ordered pair $(1,-1)$ is a solution

case e) $(7,12)$

Substitute the value of x and y in the inequality

$12\leq2*7-3$

$12\leq11$ -------> is False

The ordered pair $(7,12)$ is not a solution

Verify

using a graphing tool

see the attached figure

the solution is the shaded area below the line

The points A and D lies on the shaded area, therefore the ordered pairs A and D are solution of the inequality

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3 years ago

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Simplify the expression: 7r2+5r2+9r

jenyasd209 [6]

Answer:

9r+7r+9r

Step-by-step explanation:

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3 years ago

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Need help really fast will mark brainliest

Volgvan

I’m pretty sure it’s a

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3 years ago

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Approximately 12.6% of all (untreated) Jonathan apples had bitter pit in a study conducted by the botanists Ratkowsky and Martin

bagirrra123 [75]

Answer:

Step-by-step explanation:

Let n be a random variable that represents the first Jonathan apple chosen at random that has bitter pit.

a) P(X = n) = q(n-1)p, where q = 1 - p.

From the information given, probability if success, p = 12.6/100 = 0.126

b) for n = 3, the probability value from the geometric probability distribution calculator is

P(n = 3) = 0.096

For n = 5, the probability value from the geometric probability distribution calculator is

P(n = 5) = 0.074

For n = 12, the probability value from the geometric probability distribution calculator is

P(n = 12) = 0.8

c) For n ≥ 5, the probability value from the geometric probability distribution calculator is

P(n ≥ 5) = 0.58

d) the expected number of apples that must be examined to find the first one with bitter pit is the mean.

Mean = 1/p

Mean = 1/0.126 = 7.9

Approximately 8 apples

7 0

3 years ago