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den301095 [7]
3 years ago
13

X + 5y +3z = 4 4y – z=3 6x – 2y + 4z = 0

Mathematics
1 answer:
Leno4ka [110]3 years ago
4 0

Answer:

x = \frac{1}{4}

y = \frac{3}{4}

z = 0

Step-by-step explanation:

You first need to solve for a variable, it won't be as easy as x = 3, you are looking to replace a variable with another equation.

For example, the second equation, 4y-z=3, I can either solve for y or z. It won't be a numerical value but it will get you a step closer.

4y-z=3

4y=z+3

y = \frac{z}{4} +\frac{3}{4}

Then you are able to use substitution to negate one of the variables and solve for the other two variables. I won't type that but I think you get the idea.

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<h3 />

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