Identify square root of 3 as either rational or irrational, and approximate to the tenths place.

Mathematics

1 answer:

ASHA 777 [7]3 years ago

5 0

Answer:

Irrational

$\sqrt{3}$ = approx. 1.7

Step-by-step explanation:

The square root of 3 is irrational, because 3 is not a perfect square.

For example, 4 is a perfect square, so the square root (2) will be rational.

The square root of 3 is 1.73205080757,

and we can round this to 1.7 for the tenths place

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Answer:

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

And for this case the 95% confidence interval is given by (2.13; 2.37)

We have a point of estimate for the sample mean with this formula:

$\bar X = \frac{Upper+ Lower}{2}= \frac{3.37+2.13}{2}= 2.75$

And for the margin of error we have the following estimation:

$ME= \frac{Upper -Lower}{2}= \frac{3.37-2.13}{2}= 0.62$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean