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babymother [125]
3 years ago
12

Find the product 284 times 36

Mathematics
2 answers:
artcher [175]3 years ago
6 0

Your answer to 284*36 will be 10,224.Hope this helps!

Please mark brainliest!!!!!!!!

SVEN [57.7K]3 years ago
5 0

Answer:

10,224

I just entered 284*36 into my calculator haha

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The ratio of boys to girls is 7 : 5. There are 63 boys. Choose a ratio tool and determine the number of girls.
hammer [34]

Answer:

63:45 =7:5

Step-by-step explanation:

7 goes into 63 9 times. Since you got 9 you multiply that by the ratio of girls.

9x5=45

Have a wonderful day!

4 0
3 years ago
Part A: Maci made $170 grooming dogs one day with her mobile dog grooming business. She charges $60 per appointment and earned $
malfutka [58]

Answer:

Step-by-step explanation:

part a) 170+60 x+50

part b)210+75x-10x+35

part c) logan had to pay per appointment and maci didnt

3 0
4 years ago
Read 2 more answers
How many different committees can be formed from 12 teachers and 43 students if the committee consists of 3 teachers and 4 ​stud
lara31 [8.8K]

Answer:

\displaystyle 27150200

Step-by-step explanation:

we are two conditions

  • committees can be formed from 12 teachers and 43 students
  • the committee consists of 3 teachers and 4 students

In choosing a committee, order doesn't matter; in case of teachers we need the number of combinations of 3 people chosen from 12

remember that,

\displaystyle\binom{n}{r}  =  \frac{n!}{r!(n - r)!}

with the condition we obtain that,

  • n = 12
  • r = 3

therefore substitute:

\displaystyle\binom{12}{3}  =  \frac{12!}{3!(12 - 3)!}

simplify Parentheses:

\displaystyle\binom{12}{3}  =  \frac{12!}{3! \cdot9!}

rewrite:

\rm \displaystyle\binom{12}{3}  =  \frac{12 \times 11 \times 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1}{(1 \times 2 \times 3 )\cdot1 \times 2 \times 3 \times 4 \times 5 \times 6 \times 7 \times 8 \times 9}

reduce fraction:

\rm \displaystyle\binom{12}{3}  =  \frac{12 \times 11  \times 10}{1 \times 2 \times 3 }

rewrite 12 and 10:

\rm \displaystyle\binom{12}{3}  =  \frac{3 \times 2 \times 2 \times 11  \times 10}{1 \times 2 \times 3 }

reduce fraction:

\rm \displaystyle\binom{12}{3}  =  2 \times 11  \times 10

simplify multiplication:

\rm \displaystyle\binom{12}{3}  =  220

In case of students we need the number of combinations of 4 students choosen from 43 therefore,

\displaystyle\binom{43}{4}  =  \frac{43!}{4!(43 - 4)!}

simplify which yields:

\displaystyle\binom{43}{4}  = 123410

hence,

The committee of 7 members can be selected in BLANK different ways is

\displaystyle  123410 \times 220

\displaystyle \boxed{27150200}

and we're done!

8 0
3 years ago
In △ABC, point P∈ AB is so that AP:BP=1:3 and point M is the midpoint of segment CP . Find the area of △ABC if the area of △BMP
ddd [48]

M is mid point of CP. M will divide the \Delta BPC in two equal parts \Delta BMC and    \Delta BMP.

Area of \Delta BMP is equal to 21m^2

Since, \Delta BMC = \Delta BMP

Area of  \Delta BPC = Area of  \Delta BMC +Area of \Delta BMP =  21 + 21 = 42m^2

and since ratio of AP:BP =1:3  so the area of \Delta BMP will be 1/3 of Area of \Delta ABC

hence, Area of \Delta ABC = 63m^2

5 0
3 years ago
Read 2 more answers
6. Find the number of segments (chords) that can be drawn for each of the following:
Gnesinka [82]

Answer:

a) 10

b) 15

c) 190

d) {n \choose 2} = \frac{n!}{(n-2)!2!}

Step-by-step explanation:

Lets start with the generic item (d). In order to draw a chord we need to pick two endpoints from the total of n points of the circle and draw the line between them. The total amount of lines we can draw is equivalent to the total pair of points we can pick to draw them.

In other words, we can draw as many chords as the amount of subsets of 2 elements we can pick from a set of n. That number is the combinatorial number of n with 2 given by

{n \choose 2} = \frac{n!}{(n-2)!2!}

a) If n = 5, the answer is

{5 \choose 2} = \frac{5!}{(5-2)!2!} = \frac{120}{6*2} = 10

there are 10 possibilities

b) for n = 6

{6 \choose 2} = \frac{6!}{(6-2)!2!} = \frac{720}{24*2} = 15

15 possibilities

c) for n = 20, we have

{20 \choose 2} = \frac{20!}{(20-2)!2!} = 190

possibilities.

I hope that works for you!

6 0
3 years ago
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