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ELEN [110]
3 years ago
13

Which pairs are solutions to the equation?

Mathematics
1 answer:
klio [65]3 years ago
8 0
The answer is C) (1,7)and (7,1). In order to find the correct answer ,just substitute the numbers for x and y in the problem,so:5(1)(7)+9=44 .35+9 =44,44=44 ,so that's true .Then check the other set of given numbers by substituting for x and y :5(7)(1)+9=44,35*1=35+9= 44,therefore 44=44 ,so both sides are true.*Also remember x is always the first number given,and then y.*
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If the Volume of a Cone is 37.68inº and height is 9in, what is the diameter?
shtirl [24]

Answer:

37.68inº

Step-by-step explanation:

4 0
3 years ago
3. Given the directed line segment AB, with endpoints A20, 6) and B(-16, 50), find the point Q
garri49 [273]

The point Q that partitions the line segment is Q(2,28)

Given that the directed line segment AB, with endpoints A(20, 6) and B(-16, 50) and divide the segment into a 1:1 ratio.

A line segment is a part of a line bounded by two distinct endpoints and containing all the points of the line segment between its endpoints.

We will find the point Q by using the section formula that is

Q(x,y)=((mx₂+nx₁)/(m+n),(my₂+ny₁)/(m+n))

The given ratio is m:n=1:1 and the points (x₁,y₁)=(20,6) and (x₂,y₂)=(-16,50).

Firstly, we will find the point Q for x-axis, we get

Q(x)=(mx₂+nx₁)/(m+n)

Q(x)=(1×(-16)+1×20)/(1+1)

Q(x)=(-16+20)/2

Q(x)=4/2

Q(x)=2

Now, we will find the point Q for y-axis, we get

Q(y)=(my₂+ny₁)/(m+n)

Q(y)=(1×50+1×6)/(1+1)

Q(y)=(50+6)/2

Q(y)=56/2

Q(y)=28

The point Q that partitions the line segment is Q(x,y)=(2,28)

Hence, point Q partitions this segment into a 1:1 ratio with directed line segment AB, with endpoints A(20, 6) and B(-16, 50) is Q(2,28).

Learn more about the line segment from here brainly.com/question/9034900

#SPJ9

8 0
2 years ago
9. Zuleyka compró una bicicleta por $149. Pagó un pronto de $50. Si pagó $9
kompoz [17]

Answer:

h s m s dhoni bold sin men farhan akhtar ne

5 0
3 years ago
Graph on a number line and solve. (-4) + 8 =
grigory [225]

Answer:

its 4

Step-by-step explanation:

3 0
3 years ago
Write a polynomial in standard form with zeros at -2 and 3 !!!!! PLZ HELP
lara31 [8.8K]

If the zeros are -2 and 3, then the factored form would be

(x+2) and (x-3)  

-2+2 = 0 and 3-3 = 0

A polynomial is written as ax^2 + bx + c

Expand (x+2) (x-3) using FOIL: Multiply each tern in one set of parenthesis by each term in the other set and then simplify by combining like terms:

x*x + x*-3 + 2*x + 2*-3

x^2 -3x + 2x -6

Polynomial in standard form:

x^2 -x -6

3 0
3 years ago
Read 2 more answers
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