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ELEN [110]
2 years ago
13

Which pairs are solutions to the equation?

Mathematics
1 answer:
klio [65]2 years ago
8 0
The answer is C) (1,7)and (7,1). In order to find the correct answer ,just substitute the numbers for x and y in the problem,so:5(1)(7)+9=44 .35+9 =44,44=44 ,so that's true .Then check the other set of given numbers by substituting for x and y :5(7)(1)+9=44,35*1=35+9= 44,therefore 44=44 ,so both sides are true.*Also remember x is always the first number given,and then y.*
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3 years ago
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leonid [27]

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Step-by-step explanation:

8 0
3 years ago
25x^2+1=5 quadratic
Olenka [21]
25x² + 1 = 5

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(5x)² - (2)² = 0

(5x - 2)(5x + 2) = 0

5x - 2 = 0    or          5x + 2 = 0

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x = 2/5                      x = -2/5

x = 0.4                      x = -0.4 
 

x = + 0.4  or -0.4
3 0
2 years ago
Can u guy give me the AWNSER for number 3 or which ever on u know the Awnser to plz
FinnZ [79.3K]
3. Three and four tenths. 3+0.4=3.4
4. Two and fifty-one hundredths. 2+0.51=2.51
5. 8/10
6. 0.05
7. 46/100
8. 0.6
9. 9/10
10. 0.35

1 and 2 are correct btw
3 0
3 years ago
0.27=_ hundredths<br><br>please help me​
Alexeev081 [22]

Answer:

27 hundredths

Step-by-step explanation:

.2 is in the tenths place,

.07 is in the hundredth place,

.27 is 27 hundredths

4 0
3 years ago
Read 2 more answers
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