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madam [21]
3 years ago
15

2. After looking a table, Taylor says the constant of proportionality is 400/100

Mathematics
1 answer:
azamat3 years ago
4 0
Interesting statement
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Given △ABC, use a dilation with the center at the origin to make a similar triangle with side lengths three times as large. What
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The image of the dilation is shown below, with the centre of dilation (0,0) and scale factor of 3

The coordinate of C' is (6, -3) which is three times of the coordinate of C(2, -1)

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If A=(-1,-3) and B=(11,-8), what is the length of line ab?
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Hi!

A=(-1,-3) \ and \ B=(11,-8)\\\\|AB|=\sqrt{(11-(-1))^2+(-8-(-3))^2}\\\\|AB|=\sqrt{(11+1)^2+(-8+3)^2}\\\\|AB|=\sqrt{12^2+(-5)^2}\\\\|AB|=\sqrt{144+25}\\\\|AB|=\sqrt{169}\longrightarrow\boxed{|AB|=13}

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What is the axis of symmetry of the function f(x) = 2x^2 - 4x + 5
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7 0
3 years ago
A parking garage charges a $2.50 daily fee plus an hourly rate of $4.00. If you have $12.50 to pay for parking, how long can you
Vesnalui [34]

Step-by-step explanation:

First we need to set up an equation so

12.50=4x+2.50

Simplify each side by subtracting the initial fee of 2.50

10=4x

divide by 4 to isolate x

2.5=x

You can park for 2.5 hours with your budget

8 0
3 years ago
Determine the volume of the solid that lies between planes perpendicular to the x-axis at x=0 and x=4. The cross sections perpen
OverLord2011 [107]

Answer:

Volume = 16 unit^3

Step-by-step explanation:

Given:

- Solid lies between planes x = 0 and x = 4.

- The diagonals rum from curves y = sqrt(x)  to  y = -sqrt(x)

Find:

Determine the Volume bounded.

Solution:

- First we will find the projected area of the solid on the x = 0 plane.

                              A(x) = 0.5*(diagonal)^2

- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,

                              A(x) = 0.5*(sqrt(x) + sqrt(x) )^2

                              A(x) = 0.5*(4x) = 2x

- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:

                              V = integral(A(x)).dx

                              V = integral(2*x).dx

                               V = x^2

- Evaluate limits 0 < x < 4:

                               V= 16 - 0 = 16 unit^3

3 0
3 years ago
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