I believe the answer is D. A reactant that is catalyze a by an enzyme.
Answer:
The correct answers is: I would predict that animals with longer loops of Henle would be able to concentrate their urine more than animals with shorter loops, and thus they would more likely survive in desserts and other dry areas.
Explanation:
The<em> Loop of Henle</em> is a tubule system that connects the proximal convoluted tubule to the distal convoluted tubule in a nephron, the functional and structural unit of the kidney. Its primary job is to establish a concentration gradient in the kidney's medulla by creating a high urea concentration deep in the medulla using a countercurrent multiplier system that uses electrolyte pumps. Through this mechanism, <u><em>water is reabsorbed to concentrate the urine and impede dehydration</em></u>.
The length of the loops of Henle is of great importance for the countercurrent multiplier system - <u>the longer they are, the more concentrated the urine can get</u>. Therefore, animals with longer loops can survive better in habitats where there is not much water around.
The polar nuclei of the center cell
Answer:
Explanation:
c. Transcription of one DNA strand results in mRNA, which is a complementary copy of the information in the DNA.
a. The mRNA leaves the nucleus and goes to a ribosome open choices for ranking.
b. The building blocks of proteins, are carried to the ribosome by tRNAsAmino acids.
The process of deoxyribonucleic acod starts with replication to transcription and translation.
Replication involves the formation of a complementary base from a old or template DNA Strand this then serve as a template for transcription.
transcription involves the coping of information on the DNA to an intermediate mRNA ( messanger ribonucleic acid) in the nucleus which then move from the nucleus to ribosome in the cytoplasm where translation occurs.
Translation is the conversion of the information on the mRNA to an amino acid with the help of enzyme transferse ribonucleic acid(tRNA).
Hence the arrangement is from C ---- A-----B.
When an area is malaria-free, the HbS allele frequency is between 0 and 2.02. Thus, option "A" is correct.
<h3>How, explain your answer briefly?</h3>
In the two maps that show the allele frequency of sickle haemoglobin (HbS) and malaria endemicity in Africa, it can be seen that in the regions with no malarial outbreak or malaria-free areas coincide with the grey to lighter shades of red in the heat map of the allele frequency of HbS. The colour coding in the heat map for the allele frequency tells us that the frequencies range from 0 to 2.02 in the malaria-free areas.
Hence the answer is A)When an area is malaria-free, the HbS allele frequency is between 0 and 2.02.
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