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Hoochie [10]
3 years ago
7

-1 and 3/5 divided by (-2/3) as a mixed number

Mathematics
1 answer:
goblinko [34]3 years ago
4 0

Answer:

2 2/5

Step-by-step explanation:

change -1 3/5 to an improper fraction

-1 3/5 = -(5*1+3)/5 = -8/5

-1 3/5 ÷ -2/3 =

-8/5 ÷-2/3

copy dot flip

-8/5 * -3/2

24/10

divide top and bottom by 2

12/5

change back to a mixed number

5 goes into 12  2 times (5*2=10) with 2 left over

2 2/5

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Step-by-step explanation:

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Answer:

a=3 and b=5.

Step-by-step explanation:

So I believe the problem is this:

\frac{2(4x+3)}{x-3}(x+7)}=\frac{a}{x-3}+\frac{b}{x+7}

where we are asked to find values for a and b such that the equation holds for any x in the equation's domain.

So I'm actually going to get rid of any domain restrictions by multiplying both sides by (x-3)(x+7).

In other words this will clear the fractions.

\frac{2(4x+3)}{x-3}(x+7)}\cdot(x-3)(x+7)=\frac{a}{x-3}\cdot(x-3)(x+7)+\frac{b}{x+7}(x-3)(x+7)

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As you can see there was some cancellation.

I'm going to plug in -7 for x because x+7 becomes 0 then.

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Now we have:

2(4x+3)=a(x+7)+b(x-3) with b=5

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Divide both sides by 10:

\frac{30}{10}=a

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So a=3 and b=5.

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