Answer: 1020 ways
Step-by-step explanation:
Let C= comedy
Let M= Mystery
Number of movies(comedy) = 10
Number of movies (mystery) = 10
The total number of movies from which selection is to be made is 10 + 10
= 20
We want to pick 3 movies from 10 comedies and 10 mysteries with at least one mystery.
The selection will be from;
Unconditional selection - (0 mysteries)
=unconditional selection - ( all comedy included)
= 20C3 - 10C3 For combination, [nCr = n! /(n-r) r! ]
= [20!/(20-3)!3!] - [10!/(10-3)!3!
= (6840/6) - (720/6)
= 1140 - 120
= 1020 ways
Answer:
linear
Step-by-step explanation:
y is always 1 behind x
1 = sin²0 + cos²0
sin²0 = 1 - cos²0
sin²0 = 1 - 11/36
sin²0 = 25/36
sin 0 = 5/6 or -5/6
In the first quadrant, the values for sin, cos and tan are positive.
sin0 = 5/6
