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Masteriza [31]
4 years ago
8

Billy is participating in a biggest loser competition. His goal is to lose 3 pounds a week. If Billy meets his goal every week f

or 6 weeks, how much weight will he lose?
Mathematics
1 answer:
dezoksy [38]4 years ago
4 0

Answer:

18 pounds

Step-by-step explanation:

if billy is losing 3 pounds every week for six weeks then you would just multiply 3x6 3 being how many pounds and 6 being the number of weeks that it took

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A wall made of 5 concrete blocks weighs 11 pounds. How much does
kkurt [141]

Answer:

Each block weighs 2.2 lbs

Step-by-step explanation:

I calculated the unit rate by dividing 11 by 5, and got 2.2. To prove this is right, I multiplied 2.2 by 5 and got 11, which means this is correct.

8 0
3 years ago
What is the modulus of the complex number 5 + 2i ?
kicyunya [14]

Answer:

modulus of complex number is \sqrt{29}

Step-by-step explanation:

z=x+iy is a complex numbers

the given complex number is 5+2i

the value of x is 5  and y is 2

the modulus of complex number formula is

|z|=\sqrt{x^2+y^2} =\sqrt{5^2+2^2} =\sqrt{25+4} =\sqrt{29}

modulus of complex number is \sqrt{29}

6 0
3 years ago
Find the percent decrease. Round to the nearest percent.
xenn [34]

Answer:

It should be -3.125%

Step-by-step explanation:

(124 - 128)/128 × 100

-4/128 × 100 = -3.125%

6 0
3 years ago
Read 2 more answers
Why mathematics is important for artificial intelligence and machine learning?
AlexFokin [52]

Answer:

it helps us understand the more of the society around us and how ir works

<em>HOPE IT HELPS :)</em>

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The data represent a random sample of the number of home fire started by candles for the past several years (data are from the n
Talja [164]

Answer:

7041.43-3.71\frac{1610.27}{\sqrt{7}}=4783.43  

7041.43+3.71\frac{1610.27}{\sqrt{7}}=9299.43  

So on this case the 99% confidence interval would be given by (4783.43;9299.43)  

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

For this case we have the following data:

5460 5900 6090 6310 7160 8440 9930

And for this case we can calculate the mean and deviation with the following formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

\bar X=7041.43 represent the sample mean  

\mu population mean (variable of interest)  

s=1610.27 represent the sample standard deviation  

n=7 represent the sample size  

Calculate the confidence interval

The confidence interval for the mean is given by the following formula:  

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n-1=7-1=6  

Since the confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,6)".And we see that t_{\alpha/2}=3.71

Now we have everything in order to replace into formula (1):  

7041.43-3.71\frac{1610.27}{\sqrt{7}}=4783.43  

7041.43+3.71\frac{1610.27}{\sqrt{7}}=9299.43  

So on this case the 99% confidence interval would be given by (4783.43;9299.43)  

5 0
3 years ago
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